From equation of motion v^2 = u^2 +2aS
Hence, the final velocity is 40 m/s.
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Answer:
2.000.000.000
Explanation:
Apply the formula:
Work = Force . Displacement
W = 500.10 . 400.000 (the 10 come from gravity)
W = 5000 . 400.000
W = 2.000.000.000 Joules
I think it is that, can be wrong.
Answer:
- 5436 J
Explanation:
mass of car, m = 120 kg
radius of loop, r = 12 m
velocity at the bottom (A) = Va = 25 m/s
Velocity at the top(B) = Vb = 8 m/s
Vertical distance from A to B = diameter of loop, h = 2 x 12 = 24 m
by use of Work energy theorem
Work done by all the forces = change in kinetic energy of the body
Work done by the force + Work done by the friction = Kinetic energy at B - kinetic energy at A
- m x g x h + Work done by friction = 0.5 x 120 x (Vb^2 - Va^2)
- 120 x 9.8 x 24 + Work done by friction = 60 x (64 - 625)
- 28224 + Work done by friction = - 33660
Work done by friction = -33660 + 28224 = - 5436 J
