Answer:
Assuming air resistance is negligible, all of the potential energy that the object has at the top of the ramp is converted into kinetic energy by the time it gets to the bottom of the ramp. This is because no matter what path the object takes to move the 5m vertically (ie. falling straight down v. sliding on the ramp), gravity does the same amount of work on it.
Thus, calculate the total amount of potential energy at the top of the ramp:
Ep=mgh
Ep=4(9.81)5
Ep=196.2 Joules
Because all of this potential energy is converted into kinetic energy in the object by the bottom of the ramp, the object hits the spring with 196.2J of energy.
By using the formula for elastic potential energy, you can calculate exactly how far the spring compresses.
196.2=(1/2)k(x^2)
392.4=(350)(x^2)
1.1211=x^2
sqrt(1.1211)=x
x=1.059m
As for the last part of the question, after the object compresses the spring fully and stops momentarily, the spring converts it's elastic potential energy back into kinetic energy in the object and pushes it away again.
Explanation:
Answer:
As the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.
Explanation:
Ohm's law states that the current flowing through a circuit is directly proportional to the applied voltage.
V = IR
where;
I is the current
R is the resistance
V is the applied voltage
Based on this law (Ohm's law), as the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.
Whenever we move, we alter the rate at which we move into the future. This statement is true.
V=IR (voltage equals current<span> times </span>resistance<span>). So </span>if<span> the voltage </span>increases<span>, then the </span>current increases<span> provided that the </span>resistance remains constant<span>.</span>
Answer: 2.67 m/s^2
Explanation:
Centripetal acceleration is defined as v^2/r; in this case, it's 2^2/1.5, which is 2.67.
