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3 years ago

A ball is dropped from the top of a building.

Physics

2 answers:

son4ous [18]3 years ago

8 0

Kinetic energy is greatest at the lowest point of a roller coaster and least at the highest point

olga nikolaevna [1]3 years ago

5 0

Answer:

Right before it hits the ground.

Explanation:

It has the most kinetic energy at the very end of its descent when it is moving the fastest.

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When the current through an electromagnet ceases, what generally happens to the magnetic field?

kati45 [8]

When the current flow ceases, the magnetic flow also decreases

3 0

2 years ago

Answer this please.____

ad-work [718]

Answer:

Explanation:

When a liquid is heated, the particles are given more energy. They start to move faster and further apart. At a certain temperature, the particles break free of one another and the liquid turns to gas. This is the boiling point.

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3 years ago

What is the farthest distance parallaxes can be used to measure star distances from Earth?

JulsSmile [24]

Using current technology, useful parallax measurements can only be found for stars up to about 340 light years (100 parsecs) away.

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2 years ago

Time dilation: A missile moves with speed 6.5-10 m/s with respect to an observer on the ground. How long will it take the missil

tatyana61 [14]

Answer:

The time taken by missile's clock is $4.6\times 10^{6} s$

Solution:

As per the question:

Speed of the missile, $v_{m = 6.5\times 10^{3}} m/s$

Now,

If 'T' be the time of the frame at rest then the dilated time as per the question is given as:

T' = T + 1

Now, using the time dilation eqn:

$T' = \frac{T}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}$

$\frac{T'}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}$

$\frac{T + 1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}$

$1 + \frac{1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}$

$1 + \frac{1}{T} = (1 + (\frac{v_{m}}{c})^{2})^{- \frac{1}{2}}$ (1)

Using binomial theorem in the above eqn:

We know that:

$(1 + x)^{a} = 1 + ax$

Thus eqn (1) becomes:

$1 + \frac{1}{T} = 1 - \frac{- 1}{2}.\frac{v_{m}^{2}}{c^{2}}$

$T = \frac{2c^{2}}{v_{m}^{2}}$

Now, putting appropriate values in the above eqn:

$T = \frac{2(3\times 10^{8})^{2}}{(6.5\times 10^{3})^{2}}$

$T = 4.6\times 10^{6} s$

4 0

3 years ago

Which of the following is an example of a conductor?

nordsb [41]

Answer: B. a gold chain

7 0

2 years ago