This problem is to let you practice using Newton's second law of motion:
Force = (mass) x (acceleration)
-- The airplane's mass when it takes off (before it burns any of its load of fuel) is 320,000 kg.
-- The force available is (240,000 N/per engine) x (4 engines) = 960,000 N.
-- Now you know ' F ' and ' mass '. Use Newton's second law of motion to calculate the plane's acceleration.
Friction occurs when the surfaces and heat of two surfaces grind against each other.
I think these are the answers
Answer:
New pressure is 0.534 atm
Explanation:
Given:
Initial volume of the gas, V₁ = 250 mL
Initial pressure of the gas, P₁ = 1.00 atm
Initial temperature of the gas, T₁ = 20° C = 293 K
Final volume of the gas, V₂ = 500 mL
Final pressure of the gas = P₂
Final temperature of the gas, T₁ = 40° C = 313 K
now,
we know for a gas
PV = nRT
where,
n is the moles
R is the ideal gas constant
also, for a constant gas
we have
(P₁V₁/T₁) = (P₂V₂/T₂)
on substituting the values in the above equation, we get
(1.00 × 250)/293 = (P₂ × 500)/313
or
P₂ = 0.534 atm
Hence, the <u>new pressure is 0.534 atm</u>
Answer:
f = 632 Hz
Explanation:
As we know that for destructive interference the path difference from two loud speakers must be equal to the odd multiple of half of the wavelength
here we know that
given that path difference from two loud speakers is given as
now we know that it will have fourth lowest frequency at which destructive interference will occurs
so here we have
now for frequency we know that
Answer:
2.73×10¯³⁴ m.
Explanation:
The following data were obtained from the question:
Mass (m) = 0.113 Kg
Velocity (v) = 43 m/s
Wavelength (λ) =?
Next, we shall determine the energy of the ball. This can be obtained as follow:
Mass (m) = 0.113 Kg
Velocity (v) = 43 m/s
Energy (E) =?
E = ½m²
E = ½ × 0.113 × 43²
E = 0.0565 × 1849
E = 104.4685 J
Next, we shall determine the frequency. This can be obtained as follow:
Energy (E) = 104.4685 J
Planck's constant (h) = 6.63×10¯³⁴ Js
Frequency (f) =?
E = hf
104.4685 = 6.63×10¯³⁴ × f
Divide both side by 6.63×10¯³⁴
f = 104.4685 / 6.63×10¯³⁴
f = 15.76×10³⁴ Hz
Finally, we shall determine the wavelength of the ball. This can be obtained as follow:
Velocity (v) = 43 m/s
Frequency (f) = 15.76×10³⁴ Hz
Wavelength (λ) =?
v = λf
43 = λ × 15.76×10³⁴
Divide both side by 15.76×10³⁴
λ = 43 / 15.76×10³⁴
λ = 2.73×10¯³⁴ m
Therefore, the wavelength of the ball is 2.73×10¯³⁴ m.
