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oksian1 [2.3K]
3 years ago
7

A student throws a 130 g snowball at 6.5 m/s at the side of the schoolhouse, where it hits and sticks. What is the magnitude of

the average force on the wall if the duration of the collision is 0.18 s?
Physics
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

4.7 N

Explanation:

130 g = 0.13 kg

The momentum of the snowball when it's thrown at the wall is

p = mv = 0.13*6.5 = 0.845 kgm/s

Which is also the impulse. From here we can calculate the magnitude of the average force F knowing the duration of the collision is 0.18 s

p = F\Delta t

F*0.18 = 0.845

F = 0.845 / 0.18 = 4.7 N

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Answer: Option B: 1.3×10⁵ W

Explanation:

Power = \frac{Work \hspace{1mm} done}{Time}

P=\frac{W}{t}

Work Done, W= F.s

Where s is displacement in the direction of force and F is force.

\Rightarrow P = \frac{F.s}{t} =F \times \frac{s}{t}=F.v

where, v is the velocity.

It is given that, F = 5.75 × 10³N

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P = 5.75 × 10³N×22 m/s = 126.5 × 10³ W ≈1.3×10⁵W

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6 0
3 years ago
A substance did not change it's chemical nature in reaction which mostly likely describe the reaction
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If the substance doesn't change chemically, it is a physical reaction.
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An ant crawls 50 cm to the right, stops, and then crawls 30 cm to the left. Calculate the distance that the ant travels, and cal
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- Combine 50cm and 30cm to get 80 cm.

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- When calculating displacement, you use the initial (starting) distance. and subtract that from the final distance, giving you the displacement, or the amount traveled from the starting point to the final point if you were to make a straight line from the starting point to end point. (0 to 50, then back 30 the same direction, so subtract 30 from 50 to get 20)

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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2 years ago
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The spans of time that make up the Earth's geologic timescale are generally defined by the different types of
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5 0
3 years ago
Convert 5.5 kilometers into millimeters.​
dimaraw [331]

Answer:

5500000 millimeters

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4 0
1 year ago
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