P = I²R
where P = Power in Watts, I = Current in Ampere, R = Resistance in ohms.
P = 36<span>² * 3.9 = 5054.4
P </span>≈ 5100 watts.
<span>
Option B. </span>
Speed= distance/time
Answer=
1,800 kilometers/hour
Answer:
9.8 m / s^2
Explanation:
Assuming free fall====> there is no initial downward/upward velocity
Assuming metric units 78.4<u> m/s </u>
vf = a t
78.4 = a (8) shows a = 9.8 m/s^2
Answer:
U = 80.91 J
Explanation:
In order to calculate the electric potential energy between the three charges you use the following formula:
(1)
k: Coulomb's constant = 8.98*10^9Nm^2/C^2
q1: q2 charge
r1,2: distance between charges 1 and 2.
For the three charges you have:
(2)
You use the fact that q1=q2=q3=q and that the distance between charges are equal. Then, in the equation (2) you have:
q = 1.45μC = 1.45*10^-6C
r = 0.700mm = 0.700*10^-3m

The electric potential energy between the three charges is 80.91 J
Answer:
1
The arrow with greater impart is Arrow B
2
The both arrows will feel the same impulse
Explanation:
1. Arrow B since
it used more force to stop itself in a shorter distance.
2. They should feel the same impulse since the both had the same momentum 