<span>This problem is solved by the equation of motion:
x = x0 + v0*t + 1/2*a*t^2,
Here x0 = 0, v0 = 40ft/sec and a = -5 ft/s^2, we need to solve for t:
v = v0 + a*t, solve how long does it take to stop: 0 = v0 + a*t --> a*t = -v0 --> t = -v0/a
-- > 40/5 = 8 seconds to stop.
In this time, the car travels x = 0 + 40*8 + 0.5*-5*8^2 ft ~ 160 ft.
Answer: The car travels 160 ft.</span>
The period of the pendulum doesn't determine the length of the string.
It's the other way around.
The period of the pendulum is proportional to the square root of its length.
So if you want to triple the period, you have to make the string nine times
as long as it is now.
the initial condition is given as -
=33,000 pa
=8.0 litre i.e 8×
=300k
final state is given as-
i.e16
=300k[the temperature is constant here]
here the temperature is constant.we have to calculate the final pressure
as per the Boyle's law,
=
=16500 pa [ans]
Answer:
Proton and Neutron and nucleons
Explanation:
Answer:
This graph shows the distance moved by the train with respect to time
Between t = 3 to t = 5 the train is at rest
Since this graph shows the distance covered by the train so it is a scalar quantity
Explanation:
Here from the graph we can see the distance covered by the train with respect to time
So here from the slope of this graph we can find the speed of the train
Also from t = 3 to t = 5 we can see that slope of the graph is zero
So here n this time interval there is no motion or it is at rest
Now since we know that this is distance vs time graph so it is a scalar quantity showing in this graph
