Explanation:
A compound that contains more stronger bonds will need more amount of heat in order to break the bonds so that it changes into vapor state.
In 1-propanol, there is hydrogen bonding and it is stronger in nature. As a result, more amount of heat is required to break the bonds between molecules of 1-propanol.
Whereas in propanone, there will be dipole-dipole interactions which are less stronger than hydrogen bonding. Hence, propanone molecule will need less amount of energy than 1-propanol.
On the other hand, pentane will need more amount of heat as it has longer chain of carbon atoms as compared to methane.
Thus, we can conclude that given compounds are arranged in order of increasing vapor pressure as follows.
methane < pentane < propanone < 1-propanol
The molar mass of CO is 28 g/mol while that of CO2 is 44
g/mol. Let us calculate the total moles present in the container.
total moles = [5g / (28 g/mol)] + [5g / (44 g/mol)]
total moles = 0.2922 mol
Using PV = nRT, we get the pressure:
P = nRT / V
P = (0.2922 mol * 0.0821 L atm/mol K * 323.15 K) / 0.75 L
<span>P = 10.34 atm</span>
Answer:
Molecular formula = C₁₀H₂₀
Explanation:
Given data:
Empirical formula = CH₂
Molar mass = 140.27 g/mol
Molecular formula = ?
Solution:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Now we will calculate the empirical formula mass.
CH₂ = 12 × 1 + 1× 2
CH₂ = 12 +2
CH₂ = 14
n = 140.27 / 14
n = 1
0
Molecular formula = n (empirical formula)
Molecular formula = 10 (CH₂)
Molecular formula = C₁₀H₂₀
A.) The number of electron shells increases.
