Answer:
R = 7 [amp]
Explanation:
To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance. In this way, we have the following equation.
V = I*R
where:
V = voltage = 49 [V] (units of volts)
I = current = 7 [amp] (amperes)
R = resistance [ohms]
Now clearing R.
R =V/I
R = 49/7
R = 7 [amp]
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consider the motion in vertical direction
v = initial velocity in the vertical direction = ?
v' = final velocity in the vertical direction at the highest point = 0 m/s
a = acceleration due to gravity = - 9.8 m/s²
h = maximum height = 12.2 m
Using the kinematics equation
v'² = v² + 2 a h
0² = v² + 2 (- 9.8) (12.2)
v = 15.5 m/s
let assume that velocity of launch be v₀
θ = angle of launch = 13
vertical component of the velocity of launch is given as
v = v₀ Sinθ
15.5 = v₀ Sin13
v₀ = 69 m/s
Answer:
The resistance of each resistor is 2.5 Ω
The potential difference across each resistor is 2.4 V.
Explanation:
By Ohm's law,
<em>V </em>=<em> IR</em>
where <em>V</em> is the potential difference or voltage across an element, <em>I</em> is the current flowing through it and <em>R</em> is its effective resistance.
For the group of five resistors, let their combined resistance be <em>R</em>.
Then
(12.0 V) = (0.961 A)(<em>R</em>)

Because they are in series, <em>R</em> is the arithmetic sum of their individual resistances. Because they are all identical, the resistance of each resistor is

Also, because they are in series and are equal, the EMF is distributed across them equally. Therefore, the potential difference across each resistor is
