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enot [183]
3 years ago
13

How do you determine the speed or velocity of an object using a distance vs. time graph

Physics
1 answer:
Taya2010 [7]3 years ago
4 0
The speed of an object can be determined from the distance vs time graph.

You know that speed = distance/time

in the graph, distance/time = slope of the curve.

So SPEED IS GIVEN BY THE SLOPE of the curve in the graph.

● If the distance vs time curve is a straight line, parallel to time axis(x-axis), slope is 0. That means speed is 0. So the object is at rest.

● If the distance vs time curve is a straight line, with some non-zero slope; That means speed is nonzero and constant. So the object is in uniform motion.

● If the distance vs time curve is a curved, the slope is changing. That means speed is changing. So the object is in an accelerated motion.
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What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s2?
Mrac [35]
The correct answer is 40.5 Newtons just finished the quiz and 36.5 was incorrect.
7 0
3 years ago
Read 2 more answers
A train A travelled a distance of 150 km in 3 hours, whereas, train 'B"
ozzi

Answer:

Therefore, Train A is faster with 50km/h and a 5km/h difference

Explanation:

train A

150km/3h = 50km/h

train B

180km/4h = 45km/h

8 0
3 years ago
While brayden is traveling along a straight interstate highway, he notices that the mile marker reads 260. Brayden travels until
Yuki888 [10]

Answer:

<em>displacement = -85 miles</em>

Explanation:

<u>Displacement </u>

It's a magnitude used to measure the linear space between two points. It's computed as the subtraction of the final position minus the initial position which results in a vector. Notice the displacement only depends on the initial and final positions and not on the path the object has traveled.

Brayden starts to measure his position when the mile marker reads 260. Then he travels to the 150-mile marker and goes back to the 175-mile marker, his final position. As mentioned, the displacement only depends on the relative positions, so

displacement = 175 - 260 = -85 miles

5 0
4 years ago
What are the main forms of energy? Define each type
Fed [463]
Thermal energy - the internal kinetic energy in a substance caused by vibration of atoms and molecules. Thermal energy is also known as heat.

Radiant energy - is the electromagnetic energy that travels in waves. Radiant energy is kinetic energy that includes light, x-rays, microwaves, and radio waves.

Elastic energy - potential energy produced from stored or released elastic materials. This is stored mechanical energy energy resulting from being stretched or compressed.

Mechanical energy - the energy an object possesses due to movement. Mechanical energy is kinetic energy because it is the movement from one position to another.

Gravitational energy - the potential energy an object has because of position. This is produced from gravitational force acting upon an object.

Chemical energy - the potential energy stored in the bonds of molecules and compounds.

Nuclear energy - potential energy stored in the core (nucleus) of an atom.

Electrical energy - the kinetic energy produced from the movement of an electric charge.
4 0
4 years ago
A 1-meter-long wire consists of an inner copper core with a radius of 1.0 mm and an outer aluminum sheathe, which is 1.0 mm thic
Mazyrski [523]

Answer:

The total resistance of the wire is = 1.917\times10^{-3}

Explanation:

Since the wires will both be in contact with the voltage source at the same time and the current flows along in their length-wise direction, the two wires will be considered to be in parallel.

Hence, for resistances in parallel, the total resistance, R_{Total}

\frac{1}{R_{Total}}  =\frac{1}{R_{cu}  }+\frac{1}{R_{al}}

Parameters given:

Length of wire = 1 m

Cross sectional area of copper A_{cu}= \pi r^{2}= \pi \times (1\times 10^{-3}  )^{2} =3.142\times10^{-6} m^{2}

Cross sectional area of aluminium wire  

A_{al}= \pi( R^{2}-r^{2})\\\\ = \pi \times [ (2\times 10^{-3}  )^{2}-(1\times 10^{-3}  )^{2}] =9.42\times10^{-6} m^{2}\\

Resistivity of copper \rho _{cu}=1.7\times 10^{-8}  \Omega .m

Resistivity of Aluminium \rho _{al}=2.8\times 10^{-8}  \Omega .m

Resistance of copper R_{cu}= \frac{\rho_{cu} \times l}{A_{cu} }  =\frac{1.7\times 10^{-8} \times 1}{3.142\times10^{-6} } =5.41\times 10^{-3}\Omega

Resistance of aluminium R_{al}= \frac{\rho_{al} \times l}{A_{al} }  =\frac{2.8\times 10^{-8} \times 1}{9.42\times10^{-6} } =2.97\times 10^{-3}\Omega

The total resistance of the wire can be obtained as follows;

\frac{1}{R_{Total}}  =\frac{1}{5.41\times10^{-3}  }+\frac{1}{2.97\times10^{-3}}=521.52\frac{1}{\Omega}

R_{Total}= 1.917\times 10^{-3}\Omega

∴ The total resistance of the wire = 1.917\times 10^{-3}\Omega

4 0
3 years ago
Read 2 more answers
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