1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
enot [183]
3 years ago
13

How do you determine the speed or velocity of an object using a distance vs. time graph

Physics
1 answer:
Taya2010 [7]3 years ago
4 0
The speed of an object can be determined from the distance vs time graph.

You know that speed = distance/time

in the graph, distance/time = slope of the curve.

So SPEED IS GIVEN BY THE SLOPE of the curve in the graph.

● If the distance vs time curve is a straight line, parallel to time axis(x-axis), slope is 0. That means speed is 0. So the object is at rest.

● If the distance vs time curve is a straight line, with some non-zero slope; That means speed is nonzero and constant. So the object is in uniform motion.

● If the distance vs time curve is a curved, the slope is changing. That means speed is changing. So the object is in an accelerated motion.
You might be interested in
Please help question in photo
bonufazy [111]

Answer:

A.) the car

Explanation:

hope this helped <3

8 0
3 years ago
Is this a testable question?
faltersainse [42]
This is a non testable question because it cannot be answered by doing an experiment. But it could be modified for example Dogs are more obedient then cats.
8 0
3 years ago
Read 2 more answers
An RL circuit contains a resistor with R = 6800 Ω and an inductor with L = 2300 µH. If the impedance of this circuit is 160,000
Rainbow [258]

| Impedance | = √ [R² +(ωL)²]

R² = 6800² = 4.624 x 10⁷
 
(ωL)² = (2 · π · f · 2.3 · 10⁻³)²

          = 2.0884 x 10⁻⁴  f²

| Z | =  √[ (4.624 x 10⁷) + (2.0884 x 10⁻⁴ f²) ]  =  1.6 x 10⁵

     (1.6 x 10⁵)²  =  (4.624 x 10⁷) + (2.0884 x 10⁻⁴ f²)

     (2.56 x 10¹⁰) - (4.624 x 10⁷)  =  2.0884 x 10⁻⁴ f²


Frequency² =   (2.56 x 10¹⁰ - 4.624 x 10⁷)  /  2.0884 x 10⁻⁴

                    =       2.555 x 10¹⁰ / 2.0884 x 10⁻⁴

                    =          1.224 x 10¹⁴ 

                    =          122,400 GHz          <== my calculation

                                      11.1 MHz           <== online impedance calculator

Obviously, I must have picked up some rounding errors
in the course of my calculation. 
  











7 0
3 years ago
If τ=r×F then F.τ is equal
Mademuasel [1]
Yes that is correct.
4 0
3 years ago
De donde eres responde y te doy corona
irakobra [83]

soy de texas, united states

8 0
3 years ago
Other questions:
  • Determine a formula for the acceleration of the system in terms of mA, mB, θ, and g. Ignore the mass of the cord and pulley. Exp
    6·1 answer
  • Does air play a role in the propagation of the human voice from one end of a lecture hall to the other
    15·1 answer
  • A monatomic ideal gas in equilibrium at a pressure of 3 kPa and a temperature of 300 K is initially confined in a volume of 1.3
    13·1 answer
  • while playing her guitar , karen plucks one string with increasin levels of force. what effect does this have on the sound produ
    6·1 answer
  • Sylvia and Jadon now want to work a problem. Imagine a puck of mass 0.5 kg moving as in the simulation. Suppose that the tension
    5·1 answer
  • A steel tank of weight 600 lb is to be accelerated straight upward at a rate of 1.5 ft/sec2. Knowing the magnitude of the force
    11·1 answer
  • Identify the elements that come before iron (Fe) in the periodic table Fe, Co, Cu, K, Ni, Mn
    15·2 answers
  • The guitarist shortens the oscillating length of the properly tuned D-string by 0.15 m by pressing on the string with a finger.
    11·1 answer
  • A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before
    13·1 answer
  • Pls help me with this question its due tomorrow and I can't find the answer: A person jumped 50cm, the hang time for the jump wa
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!