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3 years ago

9

Physics conversion Convert 300 cm/min^2 into m/s^2 Please give a thorough explanation!

1 answer:

ANTONII [103]3 years ago

6 0

Answer:

8.33×10⁻⁴ m/s²

Explanation:

There are 100 cm in 1 m, and 60 s in 1 min.

300 cm/min² × (1 m / 100 cm) × (1 min / 60 s)² = 8.33×10⁻⁴ m/s²

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The number of protons equals the atomic number. TRUE OR FALSE?

Shkiper50 [21]

Answer:

true

Explanation:

The number of protons, neutrons, and electrons in an atom can be determined from a set of simple rules. The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons.

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3 years ago

if a stone is projected at an angle of 50 degrees to the horizontal with an initial velocity of 50m/s, what is the vertical comp

Vilka [71]

Answer:

38.3 m/s

Explanation:

To find vertical component of initial velocity, you'd have to use sine ratio:

$\displaystyle{\sin \theta = \dfrac{u_y}{u}}$

$\displaystyle{u_y}$ is vertical component of initial velocity and $\displaystyle{u}$ is initial velocity given which is 50 m/s.

A stone is projected at an angle of 50 degrees so $\displaystyle{\theta}$ = 50°. Substitute in the formula:

$\displaystyle{\sin 50^{\circ} = \dfrac{u_y}{50}}\\\\\displaystyle{50 \sin 50^{\circ} = u_y}\\\\\displaystyle{u_y = 38.3 \ \, \sf{m/s}}$

Therefore, the vertical component of initial velocity is approximately 38.3 m/s

(The picture is also attached for visual reference!)

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2 years ago

List things in your house and put them in order of density

ELEN [110]

I don't know what's in your house! lol. try naming things like: ball, lamp, cup, bowl.

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3 years ago

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Which of these are part of the electromagnetic spectrum?

bazaltina [42]

Answer: A, C, E

Explanation:

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3 years ago

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A defibrillator is used during a heart attack to restore the heart to its normal beating pattern. A defibrillator passes 18 A of

miskamm [114]

Answer:

q = 0.036 C

Explanation:

Given that,

Current passes through a defibrillator, I = 18 A

Time, t = 2 ms

We need to find the charge moved during this time. We know that,

Electric current = charge/time

$q=It$

Put all the values,

$q=18\times 0.002\\\\q=0.036\ C$

So, 0.036 C of charge moves during this time.

8 0

3 years ago