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2 years ago

What is the distance a truck can travel if it moves 7 m/s for 20 seconds?

2 answers:

8 0

If it moves 7 m/s and never slows down or speeds up, and it keeps doing this for 20 seconds, then it will cover 7 meters in the 1st second, 7 meters in the 2nd second, 7 meters in the 3rd second, 7 meters in the 4th second, 7 meters in the 5th second, and so on and so forth, twenty times. All together, it'll cover

7+7+7+7+7+7+7+7+7+7+7+7+7+7+7+7+7+7+7+7 meters

What I did there was: I wrote down ' 7 ' twenty times.

Now, there's a much easier way to write it.

In arithmetic, a little dot like this --> · <-- means "times", so we can write

20 · 7 and then we can work it out with our calculator or our pencil.

20 · 7 = <em> 140 meters</em> .

artcher [175]2 years ago

6 0

if it moves 7m/s, that means every second it goes 7m. Now we just multiply by the time (20 seconds) and end up with 140m.

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Which wave has a longer period and how many times, the wave with a frequency of 7000Hz or the wave with a frequency of 21.000Hz?

Nuetrik [128]

Answer:

I would say the answer is the wave of 21.000Hz

Explanation:

Because it has more frequency, and as more frequency you add, the time or longer period also increases.

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2 years ago

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3 years ago

Read 2 more answers

A car accelerates from 13 m/s to 25 m/s in 5.0 s. assume constant acceleration. what was its acceleration?

natima [27]

<span>a = 25-13/6 = 12/6 = 2 m/s^2
Av speed: 25+13/2 = 38/2 = 19 m/sec
Dist = speed * time
19 * 6 = 114 meters</span>

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2 years ago

A race car has a centripetal acceleration of 15.625 m/s2 as it goes around a curve. If the curve is a circle with radius 40 m, w

myrzilka [38]

The centripetal acceleration is given by
$a_c = \frac{v^2}{r}$
where v is the tangential speed and r the radius of the circular orbit.

For the car in this problem, $a_c = 15.625 m/s^2$ and r=40 m, so we can re-arrange the previous equation to find the velocity of the car:
$v= \sqrt{a_c r}= \sqrt{(15.625 m/s^2)(40 m)}=25 m/s$

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2 years ago

Bright and dark fringes are seen on a screen when light from a single source reaches two narrow slits a short distance apart. Th

Dima020 [189]

Answer:

Explanation:

Let the thickness of the film is t and the refractive index of the material of film is n.

When light travels through a sheet of thickness t, the optical path traveled is nt.

When the path of one of slit is covered by a sheet of thickness t, the optical path becomes

x = ( n - 1) t

As the one fringe is shift, so the optical path changed by one wavelength.

i.e., x = λ

So, λ = ( n - 1) t

$t=\frac{\lambda }{n-1}$

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3 years ago