Explanation:
We will use the equations of constant acceleration to find out
and time t.
As we know that the initial speed is zero. So
(a)
![v_{0x} = 0](https://tex.z-dn.net/?f=v_%7B0x%7D%20%3D%200)
×
m
×
m/s
![v^{2} _{x} = v^{2} _{x_{o} } + 2a_{x} (x - x_{o} )](https://tex.z-dn.net/?f=v%5E%7B2%7D%20_%7Bx%7D%20%3D%20%20v%5E%7B2%7D%20_%7Bx_%7Bo%7D%20%7D%20%2B%202a_%7Bx%7D%20%28x%20-%20x_%7Bo%7D%20%29)
![a_{x} = \frac{v^{2} _{x} - v^{2} _{ox} }{2(x - x_{o}) }](https://tex.z-dn.net/?f=a_%7Bx%7D%20%3D%20%5Cfrac%7Bv%5E%7B2%7D%20_%7Bx%7D%20-%20v%5E%7B2%7D%20_%7Box%7D%20%7D%7B2%28x%20-%20x_%7Bo%7D%29%20%7D)
= ![\frac{(3.3 * 10^{6})^{2} - 0 }{2(1.25 * 10^{-2}) }](https://tex.z-dn.net/?f=%5Cfrac%7B%283.3%20%2A%2010%5E%7B6%7D%29%5E%7B2%7D%20%20-%200%20%7D%7B2%281.25%20%2A%2010%5E%7B-2%7D%29%20%7D)
= 4.356×
m/s²
(b)
![v_{x} = v_{ox} + a_{x}t](https://tex.z-dn.net/?f=v_%7Bx%7D%20%3D%20v_%7Box%7D%20%2B%20a_%7Bx%7Dt)
![t = v_{x} - vo_{x}/a_{x}](https://tex.z-dn.net/?f=t%20%3D%20v_%7Bx%7D%20-%20vo_%7Bx%7D%2Fa_%7Bx%7D)
= 6.8870×
s
(c)
Σ![F_{x} = ma_{x}](https://tex.z-dn.net/?f=F_%7Bx%7D%20%3D%20ma_%7Bx%7D)
= (9.11×
)(4.356×
m/s²)
= 3.968×
N
Answer:
the difference in the amount of energy that charge carriers have between two points in a circuit
Explanation:
Answer:
Acceleration is zero
Explanation:
if the acceleration is zero, then the velocity-time graph is a horizontal line (i.e., the slope is zero). If the acceleration is positive, then the line is an upward sloping line (i.e., the slope is positive).
Answer:
Velocity of skater after throwing the snowball is 2.57 m/s
Explanation:
Given :
Mass of skater, M = 62.2 kg
Mass of snowball, m = 0.145 kg
Velocity of snowball relative to ground, v = 39.3 m/s
Consider v₁ be the velocity of skater after throwing the snowball.
According to the problem, initially the velocity of skater and snowball is same. So,
Velocity of skater before throwing snowball, u = 2.66 m/s
Applying conservation of momentum,
Momentum before throwing snowball = Momentum after throwing snowball
(M + m) u = Mv₁ + mv
![v_{1}=\frac{(M+m)u-mv}{M}](https://tex.z-dn.net/?f=v_%7B1%7D%3D%5Cfrac%7B%28M%2Bm%29u-mv%7D%7BM%7D)
Substitute the suitable values in the above equation.
![v_{1}=\frac{(62.2+0.145)2.66-0.145\times39.3}{62.2}](https://tex.z-dn.net/?f=v_%7B1%7D%3D%5Cfrac%7B%2862.2%2B0.145%292.66-0.145%5Ctimes39.3%7D%7B62.2%7D)
v₁ = 2.57 m/s
Yes it does work with the other body system