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3 years ago

In which of these samples do the molecules most likely have the most kinetic energy? (2 points)

1 answer:

4 0

D, water vapor. Gaseous state would have more kinetic energy, they are moving faster. If you have to compare the same state, then higher temperature would have the higher kinetic energy. But if you have solid and liquid at the same temperature - then liquid would have more.

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At what point in the cardiac cycle is pressure in the ventricles the highest (around 120 mm Hg in the left ventricle)?

skad [1K]

Answer:

Ventricular systole

Explanation:

This contraction causes an increase in pressure inside the ventricles, being the highest during the entire cardiac cycle. The ejection of blood contained in them takes place. Therefore, blood is prevented from returning to the atria by increasing pressure, which closes the bicuspid and tricuspid valves.

8 0

3 years ago

When a potential difference of 10 V is placed across a certain solid cylindrical resistor, the current through it is 2 A. If the

Keith_Richards [23]

Answer:

New Resistance = 0.5556 ohm

Explanation:

Resistance = resistivity * length /area

Here since resistivity and length are constant, we only need to see how the resistance increases or decreases with change in area.

New Area = pi * (3*D)^2 / 4

Old Area = pi * D^2 / 4

The ratio of new area / old area is :

$\frac{New Area}{Old Area} = 9$

Since area increases 9 times, and it is inversely proportional to resistance:

Resistance decreases by 9 times.

So, old resistance = Voltage / Current = 10 / 2 = 5 ohm

New Resistance = 5 / 9 = 0.5556 ohm (decreases by 9 times)

8 0

3 years ago

A ship sailing in the Gulf Stream is heading 25.0º west of north at a speed of 4.00 m/s relative to the water. Its velocity rela

ASHA 777 [7]

Answer:

Velocity of Gulf Stream= $34.5^\circ$ west of north at a speed of $2.03\ \rm m/s$

Explanation:

Given

speed of ship relative to Gulf stream= $25^\circ$ west of north at a speed of 4 m/s

speed of ship relative to earth= $5^\circ$ west of north at a speed of 4 .8 m/s

Let $V_S$ be the velocity of the ship relative to the earth and $V_{sg}$ be the velocity of the ship with respect to the Gulf stream

Let the west direction be negative x axis and north direction be positive x axis

Now

$V_{sg}=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\V_s-V_g=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\-4.8\sin5^\circ \vec i+4.8\cos5^\circ \vec j-V_g=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\Vg=-1.68\vec\ i+1.156\vec\ j\ \rm m/s\\$

magnitude of the velocity is given by

$V_g=\sqrt{(1.68^2+1.156^2)}\\V_g=2.03\ \rm m/s\\$

Let the velocity of gulf stream makes an angle $\theta$ with the positive y axis we have

$\tan\theta=\dfrac{1.156}{1.68}\\\theta=34.5^\circ$

Velocity of Gulf Stream $34.5^\circ$ west of north at a speed of $2.03\ \rm m/s$

8 0

3 years ago

Escribe verdadero o falso :

Oduvanchick [21]

By defining kinematics and derivative relations we can find which statements are true or false:

a) False. The derivative is the instantaneous velocity.

b) True. The second drift is the instantaneous acceleration.

c) False the derivative is

d) False the derivative is

a) The velocity is defined with the variation of the position with respect to time.

$v= \frac{dx}{dt}$

Wher x is the position and t the time.

In the change of the average velocity is the average value of the velocity in an interval

$v = \frac{v_f - v_o}{t}$

We can see that the derivative is the speed in a very small timet, that is, the speed instantaneous. Therefore the statement is False.

The prime derivative of the position is the instantaneous velocity, not the average velocity.

b) Acceleration is defined as the change in position with respect to time..

$a = \frac{dv}{dt}$