Light incident upon a pane of glass slows down in passing through the glass, Does it emerge at a slower speed or at its initial
1 answer:
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Answer:
5308.34 N/C
Explanation:
Given:
Surface density of each plate (σ) = 47.0 nC/m² =
Separation between the plates (d) = 2.20 cm
We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:
Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,
Now, plug in for 'σ' and
for
and solve for the electric field. This gives,
Therefore, the electric field between the plates has a magnitude of 5308.34 N/C
Answer:1.301 s
Explanation:
Given
Initial Velocity(u)=30 m/s
Height of cliff=8.3 m
Time taken to cover 8.3 m
here Initial vertical velocity is 0
Horizontal distance