All categories

4 years ago

Someone please help!!

Physics

1 answer:

mart [117]4 years ago

5 0

The answer is a.
The graph's line is higher if velocity is higher, and lower if velocity is lower. This is because the y axis is velocity. Thus, the fastest (highest velocity) that the car went is when the line was highest, and that is when x is 1.

You might be interested in

Heat always travels from

Monica [59]

Answer:

from hot toward cold. Heat moves naturally by any of three means. The processes are known as conduction, convection, and radiation. Sometimes more than one may occur at the same time.

Explanation:

4 0

3 years ago

You're driving down the highway late one night at 20 m/s when a deer steps onto the road 49 m in front of you. You reaction time

Leno4ka [110]

Answer:

v = 26.7 m/s

Explanation:

Given,

speed of the car = 20 m/s

distance between the car and the deer = 49 m

time taken to press the brake = 0.50 s

maximum deceleration of the car = 10 m/s²

Now,

distance travel by the car in 0.5 s = u x t = 20 x 0.5 = 10 m

distance travel by the car after the break is pressed

Using equation of motion

v² = u² + 2 a s

0² = 20² - 2 x 10 x s

s = 20 m

Total distance travel by the car = 20 + 10 = 30 m

Distance between deer and car = 49-30 = 19 m.

b. Maximum speed a car could have

Distance travel by the car in reaction time = v' x 0.5

v' is the maximum speed of the car.

maximum distance car can cover = 49 - 0.5 v'

Now, Using equation of motion

v² = u² + 2 a s

0² =v'² - 2 x 10 x (49- 0.5 x v')

v'² +10 v' -980 = 0

By solving

v = 26.7 m/s

Hence, maximum speed of the car can be 26.7 m/s

4 0

4 years ago

A supersonic jet is 3,600 kilometers east of U.S. airspace and has been flying for 3 hours. If the jet flies at a constant veloc

Marizza181 [45]

It will take 1.34 houra

4 0

4 years ago

A particular engine has a power output of 8 kW and an efficiency of 37%. If the engine expels 10994 J of thermal energy in each

VARVARA [1.3K]

Answer:

(a) 17450.8 J (B) 1.239 sec

Explanation:

We have given power output =8 KW

Heat expelled = 10994 j

Efficiency =37% = 0.37

(A) We know that efficiency $\eta =1-\frac{heat\ expelled}{heat\ input}$

$0.37=1-\frac{10994}{heat\ input}$

Heat input =17450.8 J

(B) Work done by the engine is = 17450.8-10994=6456.8 j

Power output is given by 8 KW =8000 W

So time for each cycle is $\frac{8000}{6456.8}=1.239 sec$

3 0

3 years ago

Suppose you have two identical capacitors. You connect the first capacitor to a battery that has a voltage of 21.2 volts, and yo

HACTEHA [7]

Answer:

r=2.743

Explanation:

The energy stored on a capacitor is of type potencial, therfore depends on the capacity to "store" energy. Inthe case of the capacitor, it stores charge (Q), and the equations you use to calculate it are:

$E_p=\frac{Q^2}{2C}=\frac{QV}{2}=\frac{CV^2}{2}$

In this case we know V and C, therefore we use the last expression:

$E_{p1}=\frac{CV_1^2}{2}$

$E_{p2}=\frac{CV_2^2}{2}$

$\frac{E_{p1}}{E_{p2}}=r=\frac{\frac{CV_1^2}{2}}{\frac{CV_2^2}{2}} \\r=(\frac{V_1}{V_2})^2\\r=(\frac{21.2}{12.8})^2$

r=2.743

3 0

3 years ago