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poizon [28]
3 years ago
15

A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40

μg/m3. The worker is inhaling air at a rate of 0.9 m3/hr. Assuming 70 kg body mass, the chronic daily intake (CDI) [mg/(kg-d)] during the period of exposure is most nearly.
Chemistry
1 answer:
Andrej [43]3 years ago
5 0

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = 40 hr/week\times 8 week = 320 hours

The concentration of xylene in the workplace =40 \mu g/m^3

The worker is inhaling air at a rate of 0.9 m^3/hr.

Amount xylene inhaled by worker in an hour :

= 40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr

Amount xylene inhaled by worker in 320 hours:

36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

\frac{24}{320}\times 11.520 mg=0.864 mg

Assuming 70 kg body mass, the chronic daily intake of xylene :

\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

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Vesna [10]

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

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so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

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Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

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8 0
3 years ago
Static electricity is
Luda [366]
Hey there !

The answer is C. build up of electrical charges by friction


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Hope this helps !
6 0
3 years ago
0.15 grams of Mg is combined with HCl to
gladu [14]

Answer:

A. 1.01

Explanation:

3 0
3 years ago
True or False: A property is a way to
kenny6666 [7]

Answer:

True

Explanation:

Here is an example: chemical properties include flammability, toxicity, acidity, reactivity. we observe the changes of these properties. Therefore, It's true.

5 0
3 years ago
How many moles are in a 275g sample of K2CrO3
Marrrta [24]

Answer:

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Explanation:

To find out number of moles, fistly we have to calculate molecular mass of K_2CrO_3.

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For molecular mass we have to add the value of mass of 2 atoms of Potassium with mass of 1 atom of Chromium and with mass of 3 atoms of oxygen.

Atomic mass of Potassium = 39

Atomic mass of Chromium = 52

Atomic mass of Oxygen = 16

Now,

Molecular mass of K_2CrO_3 = 2\times 39+52+3\times 16=78+52+48=178\ gm

The molecular mass of a compound is the mass of compound in one mole.

To find out the number of moles, we have to divide given mass of compound by its molecular mass.

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Hence the number of moles in 275 gm of K_2CrO_3 is 1.54.

8 0
3 years ago
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