Answer:
The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.
Explanation:
Number of hours worker exposed to xylene = ![40 hr/week\times 8 week = 320 hours](https://tex.z-dn.net/?f=40%20hr%2Fweek%5Ctimes%208%20week%20%3D%20320%20hours)
The concentration of xylene in the workplace =![40 \mu g/m^3](https://tex.z-dn.net/?f=40%20%5Cmu%20g%2Fm%5E3)
The worker is inhaling air at a rate of
.
Amount xylene inhaled by worker in an hour :
= ![40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr](https://tex.z-dn.net/?f=40%5Cmu%20g%2Fm%5E3%5Ctimes%200.9%20m%5E3%2Fhr%3D36%20%5Cmu%20g%2Fhr)
Amount xylene inhaled by worker in 320 hours:
![36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg](https://tex.z-dn.net/?f=36%20%5Cmu%20g%2Fhr%5Ctimes%20320%20hr%3D11%2C520%20%5Cmu%20g%3D11%2C520%5Ctimes%200.001%20mg%3D11.520%20mg)
1 μg = 0.001 mg
Amount xylene inhaled by worker in 320 hours = 11.520 mg
1 day = 24 hours
Amount xylene inhaled by worker in 1 day:
![\frac{24}{320}\times 11.520 mg=0.864 mg](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B320%7D%5Ctimes%2011.520%20mg%3D0.864%20mg)
Assuming 70 kg body mass, the chronic daily intake of xylene :
![\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day](https://tex.z-dn.net/?f=%5Cfrac%7B0.864%20mg%2Fday%7D%7B70%20kg%7D%3D0.01234%20mg%2F%20kg%20day%5Capprox%200.012%20mg%2F%20kg%20day)
The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.