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coldgirl [10]
3 years ago
9

How long does the chemical reactions take change air pollution to acid rain

Chemistry
1 answer:
Pepsi [2]3 years ago
6 0
3-5 minutes, I think
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The 3 components of air
jok3333 [9.3K]

Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).

Hope this helps :)

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How much Oxygen would be required to react with 101 g of Methane?
AlexFokin [52]

Answer:

404g

Explanation:

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3 years ago
Calculate the percentage by mass of oxygen in trioxonitrate (v) acid, (HNO3). [ H=1, N=14, O=16]​
Vadim26 [7]

Answer:

Percentage by mass of oxygen = 76.20% (Approx)

Explanation:

Given:

HNO3

H=1, N=14, O=16]

Find:

Percentage by mass of oxygen

Computation:

HNO3

Total mass = 1 + 14 + 3(16)

Total mass = 63

Mass of oxygen = (3)(16) = 48

Percentage by mass of oxygen = [48/63]100

Percentage by mass of oxygen = 76.20% (Approx)

4 0
3 years ago
What is the molar mass of a substance?
Sveta_85 [38]

Answer:

The mass in grams of one mole of a substance.

3 0
3 years ago
In an aqueous solution of a certain acid the acid is 4.4% dissociated and the pH is 3.03. Calculate the acid dissociation consta
NeX [460]

Answer:

4.1x10⁻⁵

Explanation:

The dissociation of an acid is a reversible reaction, and, because of that, it has an equilibrium constant, Ka. For a generic acid (HA), the dissociation happens by:

HA ⇄ H⁺ + A⁻

So, if x moles of the acid dissociates, x moles of H⁺ and x moles of A⁻ is formed. the percent of dissociation of the acid is:

% = (dissociated/total)*100%

4.4% = (x/[HA])*100%

But x = [A⁻], so:

[A⁻]/[HA] = 0.044

The pH of the acid can be calcualted by the Handersson-Halsebach equation:

pH = pKa + log[A⁻]/[HA]

3.03 = pKa + log 0.044

pKa = 3.03 - log 0.044

pKa = 4.39

pKa = -logKa

logKa = -pKa

Ka = 10^{-pKa}

Ka = 10^{-4.39}

Ka = 4.1x10⁻⁵

4 0
3 years ago
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