Ba(OH)₂ is a strong base, therefore completely ionises in the solution as follows
Ba(OH)₂ --> Ba²⁺ + 2OH⁻
1 mol of Ba(OH)₂ gives out 2 mol of OH⁻
therefore number of OH⁻ moles are twice the amount of Ba(OH)₂ moles in the solution
hence,
[OH⁻] = 2[Ba(OH)₂]
therefore hydroxide ion concentration = 2 x 1.37 x 10⁻⁵ M
[OH⁻] = 2.74 x 10⁻⁵ M
coefficient = 2.74
exponent = -5
Neutralization is the reaction of an acid and a base which form water and a salt
Answer:
The value is 
Explanation:
From the question we are told that
The concentration of
is ![[H^{+}] = 0.073 \ M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%200.073%20%5C%20%20M)
The concentration of
is ![[Cl{+}] = 0.073 \ M](https://tex.z-dn.net/?f=%5BCl%7B%2B%7D%5D%20%3D%20%200.073%20%5C%20%20M)
The concentration of
is ![[Ca{2+}] = 0.0090 \ M](https://tex.z-dn.net/?f=%5BCa%7B2%2B%7D%5D%20%3D%20%200.0090%20%5C%20%20M)
The concentration of
is ![[ClO^{-}] = 2 *0.0090 = 0.018](https://tex.z-dn.net/?f=%20%5BClO%5E%7B-%7D%5D%20%3D%20%202%20%2A0.0090%20%3D%20%200.018)
Generally the log of the activity coefficient is mathematically represented as

Here z is the charge which for
is +1
is the size which for
is 
is the ionic strength which is mathematically represented as

=> 
So
=>
=>
=>
Generally the pH is mathematically represented as
![pH = -log [H^{+}] * \gamma__{H^{+}}](https://tex.z-dn.net/?f=pH%20%20%3D%20%20-log%20%5BH%5E%7B%2B%7D%5D%20%2A%20%20%5Cgamma__%7BH%5E%7B%2B%7D%7D)

=> 
Answer:
S, F, Mg, Ba.
Sulfer(S) is 100pm, Fluorine(F) is 147pm, Magnesium(Mg) is 173pm, and Baruim(Ba) is 268pm.
Hope this helps <3