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photoshop1234 [79]
3 years ago
8

What phases (solid, liquid, gas) are present in the unlighted candle? In the burning candle? Which phase appears to take part in

the chemical reaction?
Chemistry
2 answers:
PSYCHO15rus [73]3 years ago
8 0
Only the solid phase.
When lit all three phases of matter are present, solid, liquid and gas. The candle itself is still solid. But liquid wax pools under the flame. And the flame itself is releasing gases consisting mostly of water vapor and carbon dioxide. Many consider the flame is in another state of matter, the plasma state. It's a high energy state of matter exhibited by stars, flames and lightning.
Feliz [49]3 years ago
5 0

Answer:

As explained below.

Explanation:

  • In an unlighted, the solid phase can be seen when it's in solid shape and not ignited when it starts to burn it's said to have entered into the liquid phase or wax phase.
  • The liquid phase is to be part of the chemical reaction because the chemical reactions are seen when it is lit with the presence of oxygen and the last phase of gas is given out in the form of flames of fire upon burning as to give out carbon dioxide and ash.

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To test the purity of sodium bicarbonate, you dissolve a 3.50g sample in water and add sulfuric acid. if 1.04g of carbon dioxide
Andrews [41]

Answer is: the percent purity of the sodium bicarbonate is 56.83 %.

1. Chemical reaction: 2NaHCO₃ + H₂SO₄ → 2CO₂ + 2H₂O + Na₂SO₄.

2. m(NaHCO₃) = 3.50 g

n(NaHCO₃) = m(NaHCO₃) ÷ M(NaHCO₃).

n(NaHCO₃) = 3.50 g ÷ 84 g/mol.

n(NaHCO₃) = 0.042 mol.

3. From chemical reaction: n(NaHCO₃) : n(CO₂) = 1 : 1.

n(CO₂) = 0.042 mol.

m(CO₂) = 0.042 mol · 44 g/mol.

m(CO₂) = 1.83 g.

4. the percent purity = 1.04 g/1.83 g  ·100%.

the percent purity = 56.8 %.

8 0
3 years ago
CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to pro
MatroZZZ [7]
The stoichiometric ratio of CuCl2 to NaCl is 1 is to 2. The stoichiometric ratio of 31.0 g CuCl2 is 26.95 grams of NaCl by converting the amount of CuCl2 to mole and multiplying by 0.5 and molar mass of NaCl.This amount is equal to 78.65% yield.
3 0
3 years ago
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Why is dilute, not concentrated, hydrochloric acid used during preparation of cyclohexaanol?
lorasvet [3.4K]
I think <span>500 m but i just think i dont know </span>
3 0
3 years ago
Calculate the molality of 75.0 grams of MgCl2 (molar mass=95.21 g/mol) dissolved in 500.0 g of solvent.
nordsb [41]

<u>Answer:</u> The molality of magnesium chloride is 1.58 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (magnesium chloride) = 75.0

M_{solute} = Molar mass of solute (magnesium chloride) = 95.21 g/mol  

W_{solvent} = Mass of solvent = 500.0 g

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m

Hence, the molality of magnesium chloride is 1.58 m

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3 years ago
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Answer: Fluorine

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