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3 years ago

5

I dropped an apple (mass 0.1kg) from the window because i'm weird. (15m above the ground). How fast was it going when it hit the

ground? plz yall what's the speed

1 answer:

Olegator [25]3 years ago

5 0

Answer:

I think the answer is 1 m per second.

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A train has a constant velocity of 2 m/s. east what is the magnitude of the horizontal acceleration of the trian?

kupik [55]

Answer:

0 m/s²

Explanation:

The velocity is constant, so there is no acceleration.

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3 years ago

A compact car has a maximum acceleration of 2.0 m/s2 when it carries only the driver and has a total mass of 1100 kg . you may w

nadya68 [22]

According to Newton`s law. Force exerted by car,

$F = m a = 1100 kg \times 2 m/s^2 = 2200 \ N$

After adding an additional 400 kg of mass, the force will be same therefore the acceleration

$F = 2200 \ N = (1100 \ kg + 400 \ kg) a \\\\ a = \frac{2200 \ N}{1500 \ kg} = 1.47 \ m/s^2$

Thus, the acceleration after adding the masses is 1.47 \ m/s^2.

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Without wildfires, forest ecosystems would be more likely to suffer from outbreaks of plant disease true or false

aivan3 [116]

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3 years ago

A "spherical capacitor" is constructed of two thin, concentric spherical shells of conducting material. Let a be the radius of t

Shalnov [3]

Answer:

$C=\frac{ab}{k(b-a)}$

Explanation:

We can assume this problem as two concentric spherical metals with opposite charges.

We have also to take into account the formulas for the electric field and the capacitance. Hence we have

$C=\frac{Q}{V}\\\\E=k\frac{Q}{r^2}\\$

Where k is the Coulomb's constant. Furthermore, by taking into account the expression for the potential and by integrating

$dV=Edr\\\\V=\int_{R_1}^{R_2}Edr=-\int_{R_1}^{R_2}\frac{kQ}{r^2}dr\\\\V=kQ[\frac{1}{R_2}-\frac{1}{R_1}]$

Hence, the capacitance is

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but R1=a and R2=b

$C=\frac{ab}{k(b-a)}$

HOPE THIS HELPS!!

3 0

3 years ago

Read 2 more answers

A car of mass 487 kg travels around a flat, circular race track of radius 53.3 m. The coefficient of static friction between the

aleksklad [387]

Answer:

9.96 m/s

Explanation:

mass of car, m = 487 kg

radius of track, R = 53.3 m

coefficient of static friction, μ = 0.19

acceleration due to gravity, g = 9.8 m/s^2

let v be the maximum speed so that the car can go without flying off the track.

The formula for the maximum speed is given by

$v_{max}=\sqrt{\mu Rg}$

$v_{max}=\sqrt{0.19\times53.3\times9.8$

vmax = 9.96 m/s

8 0

3 years ago