Porque la matematica es imposible
An isolated system , it does not allow any matter or energy to be exchanged
Answer:
Smallest drop: Water
Largest drop: Dirt
Explanation:
The heat needed to change the temperature of a sample is:
(1)
with Q the heat (added(+) or removed(-)), c specific heat, m the mass and
the change in temperature of the sample. So, if we solve (1) for
Sample A:


Sample B:


Sample C:


Note that the numbers 16744, 5400, 9450 are in the denominator of the expression
that gives the drop on temperature. so, if Q is the same for the three samples the smallest denominator gives the largest drop and vice versa.
So, the smallest drop is Sample A and the largest is Sample C.
(Important: The minus sign of
implies the temperature is dropping)
Which of the following best describes the use of a renewable resource?
Answer:
There are areas in California that use the heat from deep in the Earth to generate electricity.
Explanation:
It comes from the earth itself and we use a lot of things that comes from the earth and deep within it.
Answer:
The final acceleration of the car, v = 70 m/s
Explanation:
Given,
The initial velocity of the car, u = 20 m/s
The acceleration of the car, a = 10 m/s²
The time period of travel, t = 5 s
Using the I equations of motion
v = u + at
= 20 + 10(5)
= 20 + 50
= 70 m/s
Hence, the final acceleration of the car, v = 70 m/s