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ludmilkaskok [199]
3 years ago
8

At constant temperature and pressure, 2.05 g of oxygen gas O2 is added to a 1.0 L balloon containing 1.00 g of O2. What is the n

ew volume of the balloon?
Chemistry
1 answer:
leonid [27]3 years ago
5 0

Answer:

1.50 L.

Explanation:

  • From the general gas law:

<em>PV = nRT,</em>

Where, P is the pressure if the gas,

V is the volume if the gas container,

n is the no. of gas moles,

R is the general gas constant,

T is the temperature of the gas.

  • At constant P and T:

n₁V₂ = n₂V₁.

V₁ = 1.0 L, V₂ = ??? L.

n₁ = mass/molar mass = (2.05 g)/(32.0 g/mol) = 0.064 mol.

  • n₂ is the no. of moles of the total gas (2.05 g + 1.0 g).

n₂ = n₁ + (1.00 g)/(32.0 g/mol) = 0.0953 mol.

<em>∴ V₂ = n₂V₁/n₁ </em>= (0.0953 mol)(1.0 L)/(0.064 mol) = <em>1.489 L ≅ 1.50 L.</em>

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Explanation:

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Answer:

\boxed {\boxed {\sf 0.797 \ g \ NaOH}}

Explanation:

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First, we must convert molecules to moles using Avogadro's Number: 6.022*10²³. This tells us the number of particles in 1 mole of a substance. In this case, the particles are molecules of sodium hydroxide.

\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}

Multiply by the given number of molecules.

1.20*10^{22} \ molecules \ NaOH *\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}

Flip the fraction so the molecules cancel out.

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\frac {1.20*10^{22} \ mol \ NaOH} {6.022*10^{23}}}

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The moles of sodium hydroxide cancel.

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The original measurement of molecules has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 0 tells us to leave the 7 in the hundredth place.

0.797 \ g \ NaOH

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