The most accurately represented John Dalton's model of the atom is: C. a tiny, solid sphere with a predictable mass for a given element
<h3>Further explanation</h3>
The development of atomic theory starts from the first term conveyed by Greek scientists who suggested that every substance has the smallest particles so that the word atomos appears, which means it cannot be divided. So, John Dalton, a British scientist put forward the hypothesis about atoms, among others:
- 1. The elements are composed of atoms which are small particles which cannot be subdivided
- 2. Atoms that make up the same element have the same properties, mass, and size, while for different elements, the properties are also different
- 3. Compounds are composed of two or more atoms in a fixed ratio
- 4. In chemical reactions, atoms after and before a reaction cannot be destroyed, only separation and reassembly occur
Point 3 shows the relationship with The Law of Constant Composition of Proust so that further research on atoms is more developed
Dalton's hypothesis is described as a solid sphere like a very small shot put ball or a bowling ball based on Dalton's hobby in bowling
<h3>Learn more</h3>
Bohr's model of the atom
brainly.com/question/1625635
Rutherford performed the gold foil experiment
brainly.com/question/1859083
The part of an atom that is mostly empty space
brainly.com/question/4089014
Keywords: atom, Dalton, a solid sphere, The Law of Constant Composition
<span>This question asksyou to apply Hess's law.
You have to look for how to add up all the reaction so that you get the net equation as the combustion for benzene. The net reaction should look something like C6H6(l)+ O2 (g)-->CO2(g) +H2O(l). So, you need to add up the reaction in a way so that you can cancel H2 and C.
multiply 2 H2(g) + O2 (g) --> 2H2O(l) delta H= -572 kJ by 3
multiply C(s) + O2(g) --> CO2(g) delta H= -394 kJ by 12
multiply 6C(s) + 3 H2(g) --> C6H6(l) delta H= +49 kJ by 2 after reversing the equation.
Then,
6 H2(g) + 3O2 (g) --> 6H2O(l) delta H= -1716 kJ
12C(s) + 12O2(g) --> 12CO2(g) delta H= -4728 kJ
2C6H6(l) --> 12 C(s) + 6 H2(g) delta H= - 98 kJ
______________________________________...
2C6H6(l) + 16O2 (g)-->12CO2(g) + 6H2O(l) delta H= - 6542 kJ
I hope this helps and my answer is right.</span>
Answer:
Explanation:
a )
m = m₀ ![e^{-\lambda t](https://tex.z-dn.net/?f=e%5E%7B-%5Clambda%20t)
m is mass after time t . original mass is m₀ , λ is disintegration constant
λ = .693 / half life
= .693 / 1590
= .0004358
m = m₀ ![e^{- 0.0004358 t}](https://tex.z-dn.net/?f=e%5E%7B-%200.0004358%20t%7D)
b )
m = 50 x ![e^{-.0004358\times 500}](https://tex.z-dn.net/?f=e%5E%7B-.0004358%5Ctimes%20500%7D)
= 40.21 mg .
c )
40 = 50 ![e^{-.0004358t](https://tex.z-dn.net/?f=e%5E%7B-.0004358t)
.8 = ![e^{-.0004358t](https://tex.z-dn.net/?f=e%5E%7B-.0004358t)
= 1.25
.0004358 t = .22314
t = 512 years .