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balandron [24]
3 years ago
15

Two neutral metal spheres on wood stands are touching. A negatively charged rod is held directly above the top of the left spher

e, not quite touching it. While the rod is there, the right sphere is moved so that the spheres no longer touch. Then the rod is withdrawn. which answer is correct?
A) Both the spheres are neutral.
b) Left sphere is negatively charged, another is charged positively.
C) Right sphere is negatively charged, another is charged positively.
D) Both the spheres are charged positively.
E) Both the spheres are charged negatively
Physics
2 answers:
FrozenT [24]3 years ago
7 0

Answer: Option (C) is the correct answer.

Explanation:

As we know that metals are able to conduct electricity so, when a negatively charges rod is kept closer to the left sphere then electrons will enter the sphere.

Since, like charges repel each other. Hence, some of the negative changes from the rod will repel the negative charges of left sphere.

As both left and right spheres are touching each other so, the electrons will move towards the right sphere. As a result, there will be too many electrons (negative charge) present on the right sphere and very less electrons present in the left sphere.

Thus, we can conclude that the statement right sphere is negatively charged, another is charged positively, is true.

Murrr4er [49]3 years ago
4 0

Answer: ITS CCCC

Explanation:

ITS CORRECT

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Help me with number 2 please
NARA [144]
The answer would be B. An example of this would be the Noble gasses. They include: Helium, Argon, Neon, and so on. They are all located on the very right side because they share similar chemical behaviours; they dont react very easily because they have a full valence shell.
3 0
3 years ago
An AC generator has an output rms voltage of 100.0 V at a frequency of 42.0 Hz. If the generator is connected across a 45.0-mH i
Rus_ich [418]

Answer:

(a) 11.8692‬ ohm

(b) 12.447 A

(c) 17.6 A

Explanation:

a)  inductive reactance Z = L Ω

    = L x 2π x F

    = 45.0 x 10⁻³ x 2(3.14) x 42

    = 11.8692‬ ohm

b) rms current

    = 100 / 8.034

    = 12.447 A

c) maximum current in the circuit

    = I eff x rac2

    = 12.447 x 1.414

    = 17.6 A

4 0
3 years ago
. Consider a fully extended arm that is rotating about the shoulder such that with a shoulder-to-hand length of 30 cm. If the ar
Rainbow [258]

Answer:

13.309 m/s²

Explanation:

Length from shoulder to hand, l = 30 cm = 0.3 m

initial velocity, u = 1 m/s

final velocity, v = 2.5 m/s

time, t = 3 s

Let the tangential acceleration is a.

by using first equation of motion

v = u + at

2.5 = 1 + 3 a

a = 0.5 m/s²

Let the centripetal acceleration is a'.

a' = v'²/l

a' = 2 x 2 / 0.3

a' = 13.3 m/s²

The tangential acceleration and the centripetal acceleration are both perpendicular to each other. So, the net acceleration is given by

A=\sqrt{a^{2}+a'^{2}}

A=\sqrt{0.5^{2}+13.3^{2}}

A = 13.309 m/s²

3 0
3 years ago
A cat is running at 24 m/s. It then accelerates at 7 m/s2. How long will it take the cat to reach a speed of 49 m/s?
kozerog [31]

Answer:

t should be 3.57 second

Explanation:

Formula used is v = u+at

In which v is final velocity, u is initial velocity, a is acceleration and t is time.

Substitute each of the info given into the formula and calculate.

49 = 24 + (7)t

t = 3.57s

8 0
4 years ago
A fixed system of charges exerts a force of magnitude 22 N on a 4.0 C charge. The 4.0 C charge is replaced with a 8.0 C charge.
Karo-lina-s [1.5K]

Answer:

44 N

Explanation:

The electrostatic forces between two charges is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is their separation

We notice that the force is directly proportional to the charges.

In this problem, initially we have a force of

F = 22 N

on a q2 = 4.0 C, exerted by a charge q1.

If the charge is doubled,

q2 = 8.0 C

This means that the force will also double, so it will be

F=22 N \cdot 2 = 44 N

3 0
3 years ago
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