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balandron [24]
3 years ago
15

Two neutral metal spheres on wood stands are touching. A negatively charged rod is held directly above the top of the left spher

e, not quite touching it. While the rod is there, the right sphere is moved so that the spheres no longer touch. Then the rod is withdrawn. which answer is correct?
A) Both the spheres are neutral.
b) Left sphere is negatively charged, another is charged positively.
C) Right sphere is negatively charged, another is charged positively.
D) Both the spheres are charged positively.
E) Both the spheres are charged negatively
Physics
2 answers:
FrozenT [24]3 years ago
7 0

Answer: Option (C) is the correct answer.

Explanation:

As we know that metals are able to conduct electricity so, when a negatively charges rod is kept closer to the left sphere then electrons will enter the sphere.

Since, like charges repel each other. Hence, some of the negative changes from the rod will repel the negative charges of left sphere.

As both left and right spheres are touching each other so, the electrons will move towards the right sphere. As a result, there will be too many electrons (negative charge) present on the right sphere and very less electrons present in the left sphere.

Thus, we can conclude that the statement right sphere is negatively charged, another is charged positively, is true.

Murrr4er [49]3 years ago
4 0

Answer: ITS CCCC

Explanation:

ITS CORRECT

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A -4.00 nC point charge is at the origin, and a second -5.50 nC point charge is on the x-axis at x = 0.800 m.
mafiozo [28]

Answer:

a. f=1.22*10^{-15} N

b. f=53.6*10^{-17} N

Explanation:

The force existing between two charges is given as

f=\frac{kq_{1}q_{2}}{r^{2}}

where q= charge,

k=constant

r= distance between the two charges

Note: this force can either be repulsive or attractive force depending on the charges involve. it is repulsive if they are similar charge and it is attractive if it is opposite charges.

Also the charge of an electron is

-1.602*10^{-19}

A. we first determine the magnitude force between the -4nC and the electron

f_{21}=\frac{kq_{1}q_{2}}{r^{2}}\\f_{21}=\frac{9*10^{10} 4*10^{-9} *1.602*10^{-19} }{0.2^{2}}\\f_{21}=\frac{57.67*10^{-18} }{0.04}\\f_{21}=1.44*10^{-15}Ni

this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis

for the -5.50nC the distance between them is 0.600m as can be seen in the diagram the magnitude of the force is

f_{23} =\frac{kq_{1}q_{2}}{r^{2}}\\f_{23}=\frac{9*10^{10} 5.50*10^{-9} *1.602*10^{-19} }{0.6^{2}}\\f_{23}=\frac{79.3*10^{-18} }{0.36}\\f_{23}=-(0.22*10^{-15})N i

this this force will be repulsive force and it points away from the electron i.e points towards the -ve x-axis.

The total net force on the electron is thus

f=f_{21}+f_{23}\\ f=1.44*10^{-15}-0.22*10^{-15}\\  f=1.22*10^{-15} N

b. at  distance of x=1.20m, this is shown on the diagram below (attachment 2)

we first determine the magnitude force between the -4nC and the electron

f_{21}=\frac{kq_{1}q_{2}}{r^{2}}\\f_{21}=\frac{9*10^{10} 4*10^{-9} *1.602*10^{-19} }{1.2^{2}}\\f_{21}=\frac{57.67*10^{-18} }{1.44}\\f_{21}=4.0*10^{-17}Ni

this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis.

for the -5.50nC the distance between them is 0.4m as can be seen in the diagram the magnitude of the force is

f_{23} =\frac{kq_{1}q_{2}}{r^{2}}\\f_{23}=\frac{9*10^{10} 5.50*10^{-9} *1.602*10^{-19} }{0.4^{2}}\\f_{23}=\frac{79.3*10^{-18} }{0.16}\\f_{23}=49.6*10^{-17}Ni

this this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis.

The total net force on the electron is thus

f=f_{21}+f_{23}\\ f=4.0*10^{-15}+49.6*10^{-17}\\  f=53.6*10^{-17} N

8 0
3 years ago
Which of the following helps to explain how hydraulic lifts work?
Gnesinka [82]

Answer : C. Pascal's principle.

Explaination : Pascal's principle (well-known as Pascal's law) states that if a closed container contains a fluid at rest, then a small change in pressure at one side of the fluid is transmitted to each and every part of the fluid and also to the walls of the container without any loss. In a hydraulic lift, we need the same mechanism to work and so we take the help of Pascal's principle.


Hence, the correct option is C. Pascal's principle.

8 0
4 years ago
Read 2 more answers
To meet a U.S. Postal Service requirement, employees' footwear must have a coefficient of static friction of 0.5 or more on a sp
Vlada [557]

Answer:

the minimum time interval is 0.77 seconds

Explanation:

given data

coefficient of static friction = 0.5

coefficient of static friction shoes= 0.825

travel s = 2.40 m

to find out

what is the minimum time interval

solution

we know newton 2nd law

force = mass × acceleration

and

force acting on person due to friction

force = coefficient of static friction shoes × mg

so we can say

coefficient of static friction shoes × mg = ma

so

a = coefficient of static friction shoes × g

and we know g is 9.8 m/s²

so

distance formula by kinematic relation

distance = ut + 0.5 × at²

here put a value and u is zero because initial speed

2.40 = 0 + 0.5  × coefficient of static friction shoes × g× t²

2.40 = 0.5  × 0.825 × 9.8 × t²

t = 0.77 s

the minimum time interval is 0.77 seconds

5 0
4 years ago
Four vehicles approach an intersection with a 4 way stop at the same time. Car B is ahead of Car A and both are in the same lane
garik1379 [7]

Answer: car D

Explanation:

4 0
3 years ago
A 44 kg block lies on a horizontal frictionless surface. A horizontal force of 110 N is applied to the block. (a) Determine the
Oksana_A [137]
44k jkjk know the answer
8 0
3 years ago
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