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solmaris [256]
3 years ago
13

If 28.0 J of work is done by an external force to move a charge from a potential of 8.0 V 8.0 V to a potential of 4.0 V , 4.0 V,

what is the change in electric potential energy?
Physics
1 answer:
jonny [76]3 years ago
5 0

Answer:

Change in electric potential energy is -28.0 J

Explanation:

Electric potential energy is defined as the work is done to move a charge particle from one position to another in space in the presence of other charge particle or electric potential.

                                               OR

Electric potential energy is also equal to the change in the configuration of the charge particles.

Thus,

Change in electric potential energy = - Work Done

According to the problem, Work Done is equal to 28 J. Thus,

Change in electric potential energy = -28 J  

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An advertisement claims that a particular automobile can "stop on a dime". What net force would actually be necessary to stop an
Luba_88 [7]

Answer:

F = 4399 KN

Explanation:

given,

mass of automobile = 890 kg

initial speed = 48 km/h

                     = 48 × 0.278 = 13.34 m/s

using equation of motion

v² = u² + 2 a × s

0 = 13.34² - 2 a ×0.018

a = \dfrac{13.34^2}{0.036}

a = 4943.21 m/s²

F   = m × a

F   = 890 × 4943.21

F   =  4399456.9 N

F = 4399 KN

hence, the  Net force is F = 4399 KN

4 0
3 years ago
A flying squirrel has a mass of 0. 765 kg. He jumps off the tree and hits the ground with 125 joules of energy. Determine how hi
uranmaximum [27]

Answer:

Height, h = 16.67 m

Explanation:

We have,

Mass of a squirrel is 0.765 kg.

He jumps off the tree and hits the ground with 125 joules of energy.

It is required to find the height up on the tree the squirrel was when it jumped.

The energy possessed by the squirrel is called its gravitational potential energy. It can be given by :

E=mgh

h is height up on the tree the squirrel was when it jumped

h=\dfrac{E}{mg}\\\\h=\dfrac{125\ J}{0.765\ kg\times 9.8\ m/s^2}\\\\h=16.67\ m

So, the squirrel will go to a height of 16.67 m.

6 0
3 years ago
A golf ball is hit with a golf club. While the ball flies through the air, which forces act on the ball? Neglect air resistance.
34kurt

To solve this problem it is necessary to apply the equation related to the Gravitational Force, the equation describes that

F = \frac{GMm}{r^2}

Where,

G = Gravitational Universal Constant

M = Mass of Earth (or Bigger star)

m = Mass of Object  (or smallest star)

r = Radius

From the statement we know that once the impact is made, the golf ball is subjected to the forces that are exerted in nature. Since the air resistance, which would represent the drag force, is ignored. Only the forces related to gravity remain.

The gravitational force carries 'pushes' or 'attracts' the body towards the earth, while the speed decreases as it reaches its maximum height.

When the ball has reached its maximum height only the force of gravity begins to act on it, generating the attraction to the earth in parabolic motion.

Therefore the correct answer is B.

6 0
3 years ago
Read 2 more answers
The acceleration of gravity is 9.8m/s2. How fast will an object be moving if it falls for three seconds?
Mice21 [21]

Answer:

Acceleration

\frac{distace}{time}

When we cross multiply, distance will be equal to acceleration multiply by time

Distance = acceleration x time

Distance = 9.8 x 3

= 29.4 m/s

7 0
2 years ago
A standard baseball has a circumference of approximately 23 cm. if a baseball had the same mass per unit volume (see tables in s
OleMash [197]

In order to determine the mass of a standard baseball if it had the same density (mass per unit volume) as a proton or neutron, we first determine the volume of the baseball. The formula to be used is V_sphere = (4/3)*pi*r^3. In this case, the radius r can be obtained from the circumference C, C = 2*pi*r. After plugging in C = 23 cm to the equation, we get r = 3.6066 cm. The volume of the baseball is then equal to 205.4625 cm^3.

Next, take note of these necessary information:

Mass of a neutron/proton = 10^-27 kg

Diameter of a neutron/proton = 10^-15 m

Radius of a neutron/proton = [(10^-15)/2]*100 = 5x10^-14 cm

<span>Thus, the density, M/V of the neutron/proton is equal to 1.9099x10^12 kg/cm^3. Finally, the mass of the baseball if it was a neutron/proton can be determined by multiplying the density of the neutron/proton with the volume of the baseball. The final answer is then a large value of 3.9241x10^14 kg.</span>
8 0
3 years ago
Read 2 more answers
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