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3 years ago

Evaluate.

1 answer:

7 0

9/10 - 2/5 + 1/3

= 5/6 (Decimal: 0.8333333)

Subtract:
9/10 - 2/5 = 9/10 - 2 . 2/5 . 2
= 9/10 - 4/10
= 9 - 4/10
= 5/10
= 1/2

The common denominator you can calculate as the least common multiple of the both denominators LCM ( 10, 5) = 10

Add: 1/2 + 1/3 = 1 . 3/2 . 3 + 1 . 2/3 . 2
= 3/6 + 2/6
= 3 + 2/6

= 5/6

The common denominator you can calculate as the least common multiple of the both denominators LCM ( 2, 3) = 6

Answer in Lowest term is: 5/6 or Decimal: 0.8333333

Hope that helps!!!

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Given f(x), find g(x) and h(x) such that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x. f(x)=−3x+4⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√3+5

iVinArrow [24]

Answer:

$h(x)=-2x+4$

$g(x)=\sqrt[3]{x}-5$

Step-by-step explanation:

Consider the given function is

$f(x)=\sqrt[3]{-2x+4}-5$

It is given that $f(x)=g(h(x))$ and neither g(x) nor h(x) is solely x.

$f(x)=\sqrt[3]{(-2x+4)}-5$

Let $h(x)=-2x+4$ , then we get

$f(x)=g(h(x))=\sqrt[3]{h(x)}-5$

Substitute h(x)=x in the above function.

$g(x)=\sqrt[3]{x}-5$

Therefore, the required functions are $h(x)=-2x+4$ and $g(x)=\sqrt[3]{x}-5$ .

Check the solutions.

$g(h(x))=g(-2x+4)$ $[\because h(x)=-2x+4]$

$g(h(x))=\sqrt[3]{-2x+4}-5$ $[\because g(x)=\sqrt[3]{x}-5]$

$g(h(x))=f(x)$

Therefore, our solution is correct.

7 0

4 years ago

Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –23x + 1

Finger [1]

Answer:

Equation of other line passing through point (6 , - 11) and parallel to given line is y = - 23 x + 127 .

Step-by-step explanation:

Given as :

The equation of one line

y = - 23 x + 12

∵ The equation of line in slope-intercept form is

y = m x + c

where m is the slope of line and c is y-intercept

Now, Compare given line with standard line equation

So, The slope of given line = m = - 23

Now, Again

Other line is passing through point (6 , - 11) and is parallel to given line

so, both the lines are parallel

For parallel line condition , Slope of both lines are equal

Let The slope of other line = M

So, M = m = - 23

Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form

y - $y_1$ = M × (x - $x_1$ )

i.e y - ( - 11) = (- 23) × (x - 6)

Or, y + 11 = - 23 × x + 138

Or, y = - 23 x + 138- 11

i.e y = - 23 x + 127

So, The equation of other line y = - 23 x + 127

Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is y = - 23 x + 127 . Answer

8 0

3 years ago

A line passes through the points (7, 10) and (7, 20) which statement is true about the line.

prohojiy [21]

Answer:

You didn't give any statements so I'll tell you that it's a vertical line.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Point F is on line segment \overline{EG} EG . Given FG=8,FG=8, EF=2x+4,EF=2x+4, and EG=4x-10,EG=4x−10, determine the numerical l

Leokris [45]

Answer:

26 units

Step-by-step explanation:

If point F is on the line segment EG, then EF+FG = EG

Given

FG=8,

EF=2x+4

EG=4x−10

Substitute the given values into the formula;

2x+4+8 = 4x−10

2x+12 = 4x-10

collect like terms

2x-4x = -10-12

-2x = -22

x = 22/2

x =11

Since EF = 2x+4

EF = 2(11)+4

EF = 22+4

EF = 26

Hence the numerical length of EF is 26 units

3 0

4 years ago

Y=1/2×-16 y=-2/3×+12 what is value of x ?

larisa86 [58]

Answer:

Is equal 54

Step-by-step explanation:

6 0

3 years ago