Question

For the following reaction, 30.1 grams of carbon disulfide are allowed to react with 95.9 grams of chlorine gas. carbon disulfide (s) + chlorine (g) carbon tetrachloride (l) + sulfur dichloride (s) What is the maximum amount of carbon tetrachloride that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams

Answer 1

Answer:

A. 52g of CCl4

B. Cl2

C. 4.44g

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

CS2(s) + 4Cl2(g) —> CCl4(l) + 2SCl2(s)

Step 2:

Determination of the masses of CS2 and Cl2 that reacted and the mass of CCl4 produced from the balanced equation. This is illustrated below:

CS2(s) + 4Cl2(g) —> CCl4(l) + 2SCl2(s)

Molar Mass of CS2 = 12 + (32x2) = 76g/mol

Molar Mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 from the balanced equation = 4 x 71 = 284g

Molar Mass of CCl4 = 12 + (35.5x4) = 154g/mol

Summary:

From the balanced equation above,

76g of CS2 reacted with 284g of Cl2 to produce 154g of CCl4.

Step 3.

Determination of the limiting reactant.

From the balanced equation above,

76g of CS2 reacted with 284g of Cl2.

Therefore, 30.1g of CS2 will react with = (30.1 x 284)/76 = 112.48g of Cl2.

We can see that it requires a higher mass of Cl2 (112.48g) compare to 95.9g that was given to react with the 30.1g of CS2 given from the question. This simply means that Cl2 is the limiting reactant and CS2 is the excess reactant.

A. Determination of the maximum mass of CCl4 produced.

The limiting reactant is used to obtain the maximum amount.

From the balanced equation above,

284g of Cl2 to produce 154g of CCl4.

Therefore, 95.9g of Cl2 will produce = (95.9 x 154)/284 = 52g of CCl4.

Therefore, the maximum mass of CCl4 produced from the reaction is 52g

B. The limiting reagent is Cl2.

C. Determination of mass of the excess reagent that remains.

CS2 is the excess reagent. The mass of CS2 that remains can be obtained as follow:

From the balanced equation above,

76g of CS2 reacted with 284g of Cl2.

Therefore Xg of CS2 will react with 95.9g of Cl2 i.e

Xg of CS2 = (76 x 95.9)/284

Xg of CS2 = 25.66g.

Mass of CS2 given = 30.1g

Mass of CS2 that react = 25.66g

Mass of CS2 that remains = (Mass of CS2 given) - (Mass of CS2 that react)

Mass of CS2 that remains = 30.1 - 25.66

Mass of CS2 that remains = 4.44g