Question seems to be missing. Found it on google:
a) How long is the ski jumper airborne?
b) Where does the ski jumper land on the incline?
a) 4.15 s
We start by noticing that:
- The horizontal motion of the skier is a uniform motion, with constant velocity

and the distance covered along the horizontal direction in a time t is

- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity
and constant acceleration
(where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is

The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is
below the horizontal
This happens when:

Substituting and solving for t, we find:

b) 143.6 m
Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:


The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:

Answer: It would take 3.23ms
Explanation: Please see the attachments below
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Answer:
Correct option is
B
3
20
cm
Given; Focal length, f=20cm
Object distance, u=−10cm
Using mirror formula.
v
1
+
u
1
=
f
1
v
1
=
f
1
−
u
1
=
20
1
−
−10
1
(∵u=−10)
=
20
1
+
10
1
=
20
3
⇒v=
3
20
cm