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Kitty [74]
3 years ago
11

What a dynamics stretch is​

Physics
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

Dynamic stretching is something that's a huge help to ones muscles prior to engaging in a physical activity. This type of exercise involves some movement, which in turn increases blood flow to specific body parts and, therefore, prepares them for use.

Explanation:

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A veritical brass rod of circular section is loaded by placing a 10 kg wt on top of it .if it's length is 1 m. it's radius of cr
Inga [223]

Answer:

4.37 * 10^-4 J

Explanation:

Energy stored :

mgΔl / 2

m = mass = 10kg ; g = 9.8m/s² ; r = cross sectional Radius = 1cm = 1 * 10-2 m

Δl = mgl / πr²Y

Y = Youngs modulus = Y=3.5 ×10^10 ; l = Length = 1m

Δl = (10 * 9.8 * 1) / π * (1 * 10^-2)²* 3.5 ×10^10

Δl = 98 / 3.5 * π * 10^6

Δl = 0.00000891267

Energy stored :

mgΔl / 2

(10 * 9.8 * 0.00000891267) / 2

= 0.00043672083 J

4.37 * 10^-4 J

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2 years ago
What are some similarities between electricity and gravity?
kow [346]
Similarity : inverse square law for strength of force compared with distance. 
5 0
3 years ago
Why do sound engineers use spongy materials in the walls? (1 point)
mihalych1998 [28]

Answer:

o to increase the frequency of sound waves. It increases the sound waves to a level of frequency that humans cannot hear so you won't be able to hear many things though the wall other then low noises like pounding.

Explanation:

I am in construction class as well as a student teacher for other construction type programs trust me :D

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8 0
3 years ago
The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth
ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

\frac{P_{1} }{\\P_2}= \frac{density * g * h_1}{density * g * h_2}

So \frac{39}{P_2}= \frac{3}{9}

Or P₂= 39 * 3 = 117 kPa

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3 years ago
What is planned goal for the Europa clipper mission
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It's being planned to launch in the 2020's
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