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Kitty [74]
3 years ago
11

What a dynamics stretch is​

Physics
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

Dynamic stretching is something that's a huge help to ones muscles prior to engaging in a physical activity. This type of exercise involves some movement, which in turn increases blood flow to specific body parts and, therefore, prepares them for use.

Explanation:

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he Hobbits are building a watchtower so they can prepare to battle in case trolls decide to attack them. One Hobbit will always
joja [24]

Answer:

5m/8

Explanation:

Function T gives the time the Hobbits have to prepare for the attack, T(k), in minutes, as a function of troll's distance, k, in meters.

Function V gives visibility from the watchtower, V(m), in meters, as a function of the height of the watchtower, m, in meters.

Therefore, T(V(m)) will give the time the Hobbits have to prepare for the troll attack as a function of the height, m, of the watchtower.

We can input m into function V to obtain the visibility from watchtower, V(m), in meters. Since visibility indicates the distance you can see, this also gives the distance of the trolls. This can then be input into function T to obtain the time that the Hobbits have to prepare for a troll attack.

Let's find T(V(m)) by substituting the formula for V(m) into function T as shown below.

T(V(M))=T(50m)

=50m/80

We can simplify this as follows:

=50m/80

=5m/8

4 0
3 years ago
You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi
Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0
3 years ago
Among the alkali earth metals, the tendency to react with other substances
padilas [110]
Answer D
In alkali earth metals reacrivity increases from top to bottom (opposite of b)
This is because as you go down, the electron shells increase by 1 shell. The farther away a shell is from the nucleus, the higher its tendency to react.
D is true because the more reactive an alkali metal is, the more vigorous the reaction will be with water.
4 0
3 years ago
Read 2 more answers
The rectangular coordinates of a point are (5.00, y) and the polar coordinates of
Otrada [13]

Answer:

Explanation:

Polar coordinates formula

Summary. To convert from Polar Coordinates (r,θ) to Cartesian Coordinates (x,y) : x = r × cos( θ ) y = r × sin( θ )

6 0
3 years ago
The electromagnetic wave that delivers a cellular phone callto
spin [16.1K]

Answer:

E=2.41\cdot 10^{-5} J

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}} (1)

  • c is the speed of light (3*10⁸ m/s)
  • μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
  • B₀ is the magnetic field

I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}

I_{average}=2.68\cdot 10^{-6} W/m^{2}

Now, let's define the relationship between power (P) and average intensity (I).

I_{average}=\frac{P}{A}

  • P is the power
  • A is the area crossed

So we can calculate the power.

P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W

Finally, energy is the product of P times time, so:

E=P\cdot t=5.37\cdot 10^{-7} \cdot 45=2.41\cdot 10^{-5} J

I hope it helps you!

5 0
3 years ago
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