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padilas [110]
3 years ago
9

What is the restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b?

Physics
2 answers:
Darina [25.2K]3 years ago
3 0
Here is the correct answer of the given question above. 
The restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b would be <span>-12a/b. 
It is solved using the formula F= -kx. Where x is the displacement and k is the spring constant. F = -(4a)(3b) and you get -12a/b. Hope this answer helps. </span>
Tatiana [17]3 years ago
3 0

F=-kx

F= - (4a) (3b)

F = -12ab

-kx

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the energy of the photons is given by the Planck relation

            E = h f

we substitute

           h f = K + Ф

           Ф= hf - K

the speed of light is related to wavelength and frequency

            c = λ f

            f = c /λ

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let's reduce the energy to the SI system

            K = 0.890 eV (1.6 10⁻¹⁹ J / 1eV) = 1.424 10⁻¹⁹ J

calculate

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we reduce to eV

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           Ф = 2.179 eV

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