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3 years ago

What is the restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b?

2 answers:

3 0

Here is the correct answer of the given question above.
The restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b would be <span>-12a/b.
It is solved using the formula F= -kx. Where x is the displacement and k is the spring constant. F = -(4a)(3b) and you get -12a/b. Hope this answer helps. </span>

Tatiana [17]3 years ago

3 0

F=-kx

F= - (4a) (3b)

F = -12ab

-kx

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1 year ago

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2 years ago

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a) See graph in attachment

b) The suvat equation to use is $v_f^2 - v_i^2 = 2as$

c) The acceleration is $a=\frac{v_f^2-v_i^2}{2s}$

d) The acceleration is $1.25 m/s^2$

e) The time needed is 8 s

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For this part, find in attachment the diagram representing this situation.

Since we are not given any particular direction for the motion, we choose the x-direction as the direction of motion of the boat.

Then we have the following:

- The initial position of the boat is $x_i = 0$ , the origin

- The final position of the boat is $x_f = 200 m$

- The initial velocity of the boat is $v_i = 20.0 m/s$

- The final velocity of the boat is $v_f = 30.0 m/s$

Note that the arrow representing the final velocity is longer than that of the initial velocity, since the final velocity is larger.

The motion of the speed boat is a uniformly accelerated motion (motion at constant acceleration), therefore we can use one of the suvat equations. In this particular problem, we know the following quantities:

$v_i = 20.0 m/s$ , the initial velocity

$v_f = 30.0 m/s$ , the final velocity

$s = x_f - x_i = 200 m$ , the displacement of the boat