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julia-pushkina [17]
3 years ago
11

Science Question please help

Physics
1 answer:
topjm [15]3 years ago
8 0

Answer:

1.29 s

Explanation:

Given:

Δy = 1.40 m

v₀ = 0 m/s

a = 1.67 m/s²

Find: t

Δy = v₀ t + ½ at²

(1.40 m) = (0 m/s) t + ½ (1.67 m/s²) t²

t = 1.29 s

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On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the
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Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

\frac{F_E}{F_G}=\frac{qE}{mg}              (1)

FE: electric force

FG: gravitational force

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g: gravitational acceleration = 9.8 m/s^2

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You replace the values of all parameters in the equation (1):

\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764

Then, the gravitational force is 0.764 times the electric force on the particle

b)

The acceleration of the particle is obtained by using the second Newton law:

F_E-F_G=ma\\\\a=\frac{qE-mg}{m}

you replace the values of all variables:

a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

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∆p=mv where v=2v. hence ∆p=m2v

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True or false forces in a force pair never cancel each other out
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