Answer:
20min = 20 × 60 = 1200sec.
Speed in m per sec.
V = 1000/1200
V = 0.833m per sec.
Explanation:
Answer:
a
The speed of wave is 
b
The new speed of the two waves is 
Explanation:
From the question we are told that
The mass of the string is 
The length is 
The tension is 
Now the velocity of the first wave is mathematically represented as

Where
is the linear density which is mathematically represented as

substituting values


So


Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )
The answer is B. good luck :)
Answer:
See below
Explanation:
Distance = 27 + 13 = 40 km
Displacement = 27 - 13 = 14 km