1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ad-work [718]
3 years ago
11

A 1.50-kg iron horseshoe initially at 550°C is dropped into a bucket containing 25.0 kg of water at 20.0°C. What is the final te

mperature of the water–horseshoe system? Ignore the heat capacity of the container and assume a negligible amount of water boils away.
Physics
2 answers:
Ber [7]3 years ago
7 0

Answer:

Te =  23.4 °C

Explanation:

Given:-

- The mass of iron horseshoe, m = 1.50 kg

- The initial temperature of horseshoe, Ti_h = 550°C

- The specific heat capacity of iron, ci = 448 J/kgC

- The mass of water, M = 25 kg

- The initial temperature of water, Ti_w = 20°C

- The specific heat capacity of water, cw = 4186 J/kgC

Find:-

What is the final temperature of the water–horseshoe system?

Solution:-

- The interaction of horseshoe and water at their respective initial temperatures will obey the Zeroth and First Law of thermodynamics. The horseshoe at higher temperature comes in thermal equilibrium with the water at lower temperature. We denote the equilibrium temperature as (Te) and apply the First Law of thermodynamics on the system:

                             m*ci*( Ti_h - Te) = M*cw*( Te - Ti_w )

- Solve for (Te):

                             m*ci*( Ti_h ) + M*cw*( Ti_w ) = Te* (m*ci + M*cw )

                             Te = [ m*ci*( Ti_h ) + M*cw*( Ti_w ) ] / [ m*ci + M*cw ]

- Plug in the values and evaluate (Te):

                             Te = [1.5*448*550 + 25*4186*20 ] / [ 1.5*448 + 25*4186 ]

                             Te = 2462600 / 105322

                             Te =  23.4 °C    

koban [17]3 years ago
4 0

Answer:

Final temperature = 23.4 °C

Explanation:

The idea here is that the heat lost by the metal will be equal to the heat gained by the water.

In order to be able to calculate the final temperature of the iron + water system, we need to know the specific heats of water and iron which are;

C_water = 4.18 J/g°C

C_iron = 0.45 J/g°C

The formula to determine the determine the amount of heat lost or gained is given by;

q = m•c•ΔT

q = heat lost or gained

m = the mass of the sample

c = specific heat of the substance

ΔT = the change in temperature, defined as final temperature minus initial temperature

Now, -q_water = q_iron

The negative sign is used here because heat lost carries a negative sign. Let's say that the final temperature of the iron + water system will be T_f

Thus, we can say that the changes in temperature for the iron and for the water will be;

ΔT_iron = T_f − 550 °C

and ΔT_water = T_f − 20 °C

This means that we will now have;

−m_iron•c_iron•ΔT_iron = m_water•c_water•ΔT_water

This now gives us ;

−m_iron•c_iron•(T_f − 550°C) = m_water•c_water•(T_f − 20°C) - - - - (eq1)

Notice that the specific heats for these two substances is given per gram. This means that you will have to

Mass of iron = 1.5 kg = 1500g

Mass of water = 25 kg = 25000 g

Plugging the relevant values into eq(1),we have;

−(1500g)•(0.45 J/g°C)•(T_f − 550°C) = (25000 g)•(4.18 J/g°C)•(T_f − 20°C)

Multiplying out to get;

-675(T_f − 550) = 104,500(T_f − 20)

-675T_f + 371,250 = 104,500T_f - 2090000

371,250 + 2090000 = 104,500T_f + 675T_f

2461250 = 105175T_f

T_f = 2461250/105175 = 23.4 °C

You might be interested in
How many electrons pass a given point in the circuit in 3 min? The fundamental charge is 1.602 × 10−19 C. amps: 0.415 , volts: 1
morpeh [17]

The no of electron passing through the circuit is current by time. The no of electron passing are  46.63 x 10¹⁹ electrons.

<h3>What is charge?</h3>

The charge is the physical quantity which attracts or repels another object when comes into its field.

The time 3 min has 3 x 60 =180 seconds.

Total Charge Q = current I x time t

Q = 0.415 x 180

Q =74.7 coulombs

The no of electrons is the ratio of total charge divided by the fundamental charge.

n = 74.7/  1.602 × 10⁻¹⁹

n= 46.63 x 10¹⁹ electrons

Thus, electrons pass a given point in the circuit in 3 min are 46.63 x 10¹⁹ .

Learn more about charge.

brainly.com/question/11944606

#SPJ1

4 0
2 years ago
What is formed in the shape of a long, low land area between hills or mountains?
DENIUS [597]
It is rectangle and it probably is a lake perhaps
3 0
3 years ago
URGENT!!!!!!!<br><br> PLEASE HELP WITH THIS PHYSICS PROBLEM
Levart [38]

Explanation:

Let

x_1 = distance traveled while accelerating

x_2 = distance traveled while decelerating

The distance traveled while accelerating is given by

x_1 = v_0t + \frac{1}{2}at^2 = \frac{1}{2}at^2

\:\:\:\:\:= \frac{1}{2}(2.5\:\text{m/s}^2)(30\:\text{s})^2

\:\:\:\:\:= 1125\:\text{m}

We need the velocity of the rocket after 30 seconds and we can calculate it as follows:

v = at = (2.5\:\text{m/s}^2)(30\:\text{s}) = 75\:\text{m/s}

This will be the initial velocity when start calculating for the distance it traveled while decelerating.

v^2 = v_0^2 + 2ax_2

0 = (75\:\text{m/s})^2 + 2(-0.65\:\text{m/s}^2)x_2

Solving for x_2, we get

x_2 = \dfrac{(75\:\text{m/s})^2}{2(0.65\:\text{m/s}^2)}

\:\:\:\:\:= 4327\:\text{m}

Therefore, the total distance x is

x = x_1 + x_2 = 1125\:\text{m} + 4327\:\text{m}

\:\:\:\:= 5452\:\text{m}

3 0
3 years ago
Suppose you were to fill a balloon with air then let go of it withoutntying it closed. What causes the balloon to fly away?
tangare [24]
What causes the ballon to fly away is the air pushing out of the balloon also tied in with air pressure
3 0
3 years ago
Read 2 more answers
A nerve signal travels 150 meters per second. Determine the number of kilometers that the nerve signal will travel in the same t
joja [24]

Explanation:

It is given that,

A nerve signal travels 150 meters per second. It is the speed of the nerve signal. We need to convert the number of kilometers that the nerve signal will travel in the same time.

We know that,

1 kilometer = 1000 meter

1 hour = 3600 seconds

150\ \dfrac{m}{s}=150\times \dfrac{1/1000\ km}{1/3600\ h}

150\ m/s=540\ km/h

So, the nerve signal will travel at the rate of 540 km/h. Hence, this is the required solution.

6 0
3 years ago
Other questions:
  • If a freely falling object were somehow equipped with a speedometer, its speed
    7·1 answer
  • (HELP ASAP)
    10·2 answers
  • Which of the following statements is true?
    9·2 answers
  • The flash on a high-tech camera contains a capacitor of 750 μ F. The battery in the camera supplies 330 V. (a) Determine the ene
    13·1 answer
  • The greater the amplitude, the greater the wave's:
    9·1 answer
  • 2.5 x 103 kilogram truck with rubber tires moves through a 120 meter radius turn on a dry asphalt surface.
    8·1 answer
  • Two planes approach each other head on. Each has a speed of 721km/h and they spot each other when they are initially 14.7km apar
    11·1 answer
  • How does weathering, erosion and deposition shape the Earth and contribute to the rock cycle? Weathering, erosion and deposition
    15·1 answer
  • Need help with dot product
    9·1 answer
  • HELP ME OUT PLEASE!!!!!
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!