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fenix001 [56]
3 years ago
6

How did Rutherford change the model of the atom?

Physics
1 answer:
miskamm [114]3 years ago
3 0
<span>A.) He used an experiment with gold foil to prove that an atom had a positive nucleus in the middle and was surrounded by negative electrons.

Hope this helps!
</span>
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When a substance goes directly from a gaseous state to a solid state as dry ice does
Naddik [55]

Answer:  Sublimation I think.

Explanation:

6 0
3 years ago
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You throw a ball straight up. The ball has an initial speed of 11.2 m/s when it leaves your hand What is the maximum height the
Jet001 [13]

Answer:

Explanation:

Given

initial velocity u=11.2\ m/s

At maximum height velocity of ball is zero

using

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

(0)^2 -(11.2)^2=2\times (-9.8)\times (s)

s=\frac{11.2^2}{2\times 9.8}

s=6.4

time taken by the ball to reach the maximum height

v=u+at

0=11.2-9.8\times t

t=\frac{11.2}{9.8}

t=1.142\ s

At t=2\ s height of ball is

h=ut+\\frac{1}{2}at^2

h=11.2\times 2-\frac{1}{2}9.8\times (2)^2

h=22.4-19.6

h=2.8\ m

i.e. ball is moving downward

height at v=5\ m/s

v^2-u^2=2as

s=\frac{25-125.4}{2\times (-9.8)}

s=5.12\ m    

8 0
3 years ago
Which amusement park ride utilizes periodic motion?
tatyana61 [14]
Any ride that oscillates back and forth or moves only in a complete circle utilizes periodic motion.
8 0
3 years ago
The average distance an electron travels between collisions is 2.0 μmμm . What acceleration must an electron have to gain 2.0×10
Ilya [14]

The solution is in the attachment

4 0
3 years ago
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a 905 - g meteor impacts the earth at a speed of 1623 m/s. if all of its energy is entirely converted to heat in the meteor, wha
nlexa [21]

Answer: 2859.78 k

Explanation: By using the law of conservation of energy, the kinetic energy of the meteor equals the heat energy.

Kinetic energy = 1/2mv^2

Heat energy = mcΔθ

Where m = mass of meteor , v = velocity of meteor = 1623 m/s

c = specific heat capacity of meteor (iron) = 460.548 j/kg/k

Δθ = change in temperature of meteor = ?

From law ofconservation of energy, we have that

1/2mv^2 = mcΔθ

By cancelling "m" on both sides, we have that

v^2/2 = cΔθ

v^2 = 2cΔθ

(1623)^2 = 2× 460.548 × Δθ

2634129 = 921.096 × Δθ

Δθ = 2634129 / 921.096

Δθ = 2859.78 k

6 0
3 years ago
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