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3 years ago

The trend of this graph is a. Negative b. Positive c. Zero

Chemistry

1 answer:

Sveta_85 [38]3 years ago

7 0

B. positive because y increases as x does. It it were negative y would decrease as x increases and it would be 0 if y stayed the same as x increases.

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What is responsible for the diffrence in the climate between northern and southern switzerland?

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3 years ago

3. Are quartz and coal minerals or only naturally occurring<br> substances?

klasskru [66]

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4 years ago

CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to react with 2 moles of CH4?

PtichkaEL [24]

<h3>Answer:</h3>

100 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 2 mol CH₄

[Solve] x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CH₄ → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 2 \ mol \ CH_4(\frac{2 \ mol \ O_2}{1 \ mol \ CH_4})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})$
Multiply/Divide: $\displaystyle 128 \ g \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

128 g O₂ ≈ 100 g O₂

3 0

3 years ago

Read 2 more answers

What is the percent-by-mass, %(m/m), concentration of sucrose ( table sugar) in a solution made by dissolving 22.8 g of sucrose

Ede4ka [16]

Answer:

32.6 %

Explanation:

Given data

Mass of sucrose (solute): 22.8 grams

Mass of water (solvent): 47.1 grams

Step 1: Calculate the mass of the solution

The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.

m(solution) = m(solute) + m(solvent)

m(solution) = 22.8 g + 47.1 g

m(solution) = 69.9 g

Step 2: Calculate the percent-by-mass of sucrose in the solution

We will use the following expression.

$\% m/m = \frac{mass\ of\ sucrose}{mass\ of\ solution} \times 100\% = \frac{22.8g}{69.9g} \times 100\% = 32.6 \%$

5 0

3 years ago

Read 2 more answers

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zheka24 [161]

It’s definitely persuade!

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2 years ago