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nordsb [41]
3 years ago
9

The trend of this graph is a. Negative b. Positive c. Zero

Chemistry
1 answer:
Sveta_85 [38]3 years ago
7 0
B. positive because y increases as x does. It it were negative y would decrease as x increases and it would be 0 if y stayed the same as x increases. 
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What mass of CO2 can be produced from the decomposition of 4.8 moles of Fe2(CO3)3?
gavmur [86]

Answer: 633.6 g of CO_2 can be produced from the decomposition of 4.8 moles of Fe_2(CO_3)_3

Explanation:

The balanced chemical equation for decomposition of Fe_2(CO_3)_2 is :

Fe_2(CO_3)_2\rightarrow Fe_2O_3+3CO_2

According to stoichiometry :

1 mole of Fe_2(CO_3)_2 produce = 3 moles of CO_2

Thus 4.8 moles of Fe_2(CO_3)_2 will rproduce=\frac{3}{1}\times 4.8=14.4moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=14.4moles\times 44g/mol=633.6g

Thus 633.6 g of CO_2 can be produced from the decomposition of 4.8 moles of Fe_2(CO_3)_3

7 0
3 years ago
What is the reactant(s) of the reaction below?
svet-max [94.6K]
Answer : C

Reason : The product is MgO which is Magnesium Oxide + CO2 which is carbon dioxide because of the 2
3 0
3 years ago
When iron rusts in air iron3 oxide is produced. How many moles of oxygen react with 28.0 mol of iron in the rusting reaction 4fe
Marrrta [24]
This the balanced equation based on the question 4Fe + 3O_2  -\ \textgreater \ 2Fe_2O_3.

We then proceed with the following calculations

28.0molFe*(\frac {3molO_2}{4mol Fe})= 21molO_2

The answer is 21molO_2 is produced.
5 0
3 years ago
The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for
tester [92]

The given question is incomplete. The complete question is:

The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change:

A. K(s)+O_2(g)\rightarrow KO_2(s)

B. CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)

C. CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

D. N_2O_2(g)\rightarrow 2NO(g)+O_2(g)

Answer: A. K(s)+O_2(g)\rightarrow KO_2(s) : decreases

B. CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2(g) : decreases

C. CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g): no change

D. N_2O_2(g)\rightarrow 2NO(g)+O_2(g) : increases

Explanation:

Entropy is defined as the randomness of the system.

Entropy is said to increase when the randomness of the system increase, is said to decrease when the randomness of the system decrease and is said to have no change when the randomness remains same.

In reaction K(s)+O_2(g)\rightarrow KO_2(s), as gaseous reactant is changed to solid product, entropy decreases.

In reaction CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g), as 4 moles of gaseous reactants is changed to 2 moles of gaseous product, entropy decreases.

In reaction CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g), as 3 moles of gaseous reactants is changed to 3 moles of gaseous product, entropy has no change.

In reaction  N_2O_2(g)\rightarrow 2NO(g)+O_2(g) , as 1 mole of gaseous reactant is changed to 3 moles of gaseous product, entropy increases.

7 0
3 years ago
What forces hold network solids together?
mezya [45]

Answer:

Covalent solids, also called network solids, are solids that are held together by covalent bonds. As such, they need localized electrons (shared between the atoms) and therefore the atoms are arranged in fixed geometries. Distortion far from this geometry can only occur through a breaking of covalent sigma bonds.

Pls help i need one more brainly to rank up. And have a great day :D

5 0
3 years ago
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