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3 years ago

Is it A?

1 answer:

6 0

This is true, it's A!

Students grades are most likely coorelated with some event that influenced them directly, or that is influenced by the same factor. Here having completed the exam revieq packet means that the students have studied, so they will likely get good grades.

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3<br> Which expression is closest in value to 5.66?

Free_Kalibri [48]

Let's consider the standard and usually used value of irrational numbers given in the question.

It is asked to see which is closed to 5.66

So, let's see the options:

A) GiveN:

$\dfrac{\pi}{2} + \pi$

Let consider π = 3.14

$\dfrac{3.14}{2} + 3.14$

$1.57 + 3.14$

$4.71 \: (approx.)$

B) GiveN:

$2\pi - 1$

Here also, let's consider the value be 3.14

$2 \times 3.14 - 1$

$6.28 - 1$

$5.28 \: (approx.)$

C) GiveN:

$4 \sqrt{2}$

Let's consider the value of √2 be 1.414

$4 \times 1.414$

$5.6516 \: (approx.)$

D) GiveN:

$8 - \sqrt{3}$

Let's consider the value of √3 be 1.732

$8 - 1.732$

$6.268 \: (approx.)$

So, we can see that we have got the approximate value of all the numericals, and the closest to 5.66 is 5.6516 which is the answer of Option C.

So, Correct answer is C

#CarryOnLearning

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6 0

3 years ago

Rationalize the numerator. <br><img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B144x%20%7D%20%7D%7B%20%5Csq

Simora [160]

rationalizing the numerator, or namely, "getting rid of that pesky radical at the top".

we simply multiply top and bottom by a value that will take out the radicand in the numerator.

$\bf \cfrac{\sqrt[3]{144x}}{\sqrt[3]{y}}~~
\begin{cases}
144=2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 3\\
\qquad 2^3\cdot 18
\end{cases}\implies \cfrac{\sqrt[3]{2^3\cdot 18x}}{\sqrt[3]{y}}\implies \cfrac{2\sqrt[3]{ 18x}}{\sqrt[3]{y}}
\\\\\\
\cfrac{2\sqrt[3]{ 18x}}{\sqrt[3]{y}}\cdot \cfrac{\sqrt[3]{(18x)^2}}{\sqrt[3]{(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)(18x)^2}}{\sqrt[3]{(y)(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)^3}}{\sqrt[3]{18^2x^2y}}$

$\bf \cfrac{2(18x)}{\sqrt[3]{324x^2y}}~~
\begin{cases}
324=2\cdot 2\cdot 3\cdot 3\cdot 3\cdot 3\\
\qquad 12\cdot 3^3
\end{cases}\implies \cfrac{36x}{\sqrt[3]{12\cdot 3^3x^2y}}
\\\\\\
\cfrac{36x}{3\sqrt[3]{12x^2y}}\implies \cfrac{12x}{\sqrt[3]{12x^2y}}$