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3 years ago

Is it A?

1 answer:

6 0

This is true, it's A!

Students grades are most likely coorelated with some event that influenced them directly, or that is influenced by the same factor. Here having completed the exam revieq packet means that the students have studied, so they will likely get good grades.

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Find the slope of each line. <br><br>y=1/4x-4

Likurg_2 [28]

Answer:

1/4

Step-by-step explanation:

y = 1/4x -4

This equation is in the form

y= mx+b where m is the slope and b is the y intercept

The slope is 1/4

6 0

3 years ago

Find the percentage of: 21% of 18 use a set of fraction operations method to find the percentage.

Pani-rosa [81]

Answer:

4.8%

Step-by-step explanation:

21% of 18

following the BODMAS rule, OF means multiplication

and also this sign% always means 100

so,it will be 21/100 * 18/1

this a laptop so i cant put it in a fraction way.....okay

this is how it shows...21/100 * 18/1

lets divide....

21/100 * 18/1

we will use 2 to divide

2 in 100=50

2 in 18=9

so it will be 21/50 * 9/1

nothing can divide so we will multiply

21*9/50*1

189/50=3.78≈4.8%

4 0

3 years ago

I will mark you as brainliest if you're answer is correct

GalinKa [24]

Answer:

perimeter = 28.13 cm

Step-by-step explanation:

Calculate the length of a line drawn from A to C.

sin 85 = b/8, b = 7.97

cos 85 = c/8, c = 0.697

AC² =7.97² + (6 + 0.697)² = 63.52 + 44.85 = 108.37

AC = 10.41

Now you have a right triangle ADC with a known hypotenuse and one leg.

Using the Pythagorean theorem:

DC² = 10.41² - 5²

DC² = 108.37 - 25 = 83.37

DC = 9.13 cm

perimeter = 5 + 6 + 8 + 9.13 = 28.13 cm

8 0

3 years ago

A 13-foot ladder is leaning against a wall. If the top slips down the wall at a rate of 2 ft/s, how fast will the foot be moving

dimulka [17.4K]

Answer:

$\frac{db}{dt}=\frac{20\sqrt{69}}{69}\approx2.4077\text{ ft/s}$

Step-by-step explanation:

We know that the ladder is 13 feet long.

We also know that the top of the ladder is slipping down at a rate of 2ft/s.

And we want to find the rate at which the foot of the ladder is moving away when the top is 10 feet above the ground.

We can use the Pythagorean Theorem for this problem:

$a^2+b^2=c^2$

Let's let a be the leg by the wall, and b be the leg on the ground.

Our hypotenuse is 13 and it stays 13. So, let's substitute 13 for c:

$a^2+b^2=(13)^2=169$

Now, let's take the derivative of both sides with respect to t:

$\frac{d}{dt}[a^2+b^2]=\frac{d}{dt}[169]$

Evaluate. Use implicit differentiation:

$2a\frac{da}{dt}+2b\frac{db}{dt}=0$

We know that the top of the ladder is slipping down at a rate of 2ft/s. So, da/dt is -2 (it's negative because it's slipping <em>downwards</em>).

We want to find db/dt when the top is 10 feet above the ground. So, substitute 10 for a.

Since a is 10 and we know that c stays constant at 13, we can figure out b using the Pythagorean Theorem:

$10^2+b^2=13^2$

Evaluate:

$100+b^2=169$

Solve for b:

$b^2=69\\b=\sqrt{69}$

So, substitute -2 for da/dt, 10 for a, and √69 for db/dt. This yields:

$2(10)(-2)+2(\sqrt{69})(\frac{db}{dt})=0$

Solve for db/dt. Multiply:

$-40+2(\sqrt{69})(\frac{db}{dt})=0$

Add 40 to both sides:

$2\sqrt{69}(\frac{db}{dt})=40$

Divide both sides by 2√69:

$\frac{db}{dt}=\frac{20}{\sqrt{69}}$

Rationalize:

$\frac{db}{dt}=\frac{20\sqrt{69}}{69}\approx2.4077\text{ ft/s}$

So, the foot will be moving at approximately 2.4077 feet per second.

7 0

3 years ago

Square GHIJ shares a common center with regular hexagon ABCDEF on a coordinate plane. AB is parallel to GH. If the combined figu

expeople1 [14]

Answer: B. 180°.

Step-by-step explanation: In the attached figure, GHIJ is a square and ABCDEF is a regular hexagon having common centre O.

A square is symmetric at a rotational angle of 90° and a regular hexagon is symmetric at a rotational angle of 60°.

So, to bring the image of the square and the hexagon back to the previous position, we need to find the LCM of both the angles.

LCM(60°,90°)=180°.

So, the correct option is B. 180°.

5 0

3 years ago

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