The power delivered to the coil is 721.31 Watts
<h3>How to determine the power</h3>
Given that;
- Power of the heating coil = 500W
- Voltage = 110V
- Diameter of the Nichrome wire = 0. 500mm, radius = 0. 500/2 = 0. 00025m
But the formula for power is given a;
Power, P = V²/R
Then , R = V²/P
R = (110)²/ 500 = 24. 2Ω
To determine the length,
Length, L = RA/ ρ
L = 24. 2 × ( 0. 0025)² × 3. 142/ 10^-6
L = 4. 32m
We also have that;
Resistance, R = Ro( 1 + α ΔT)
R = 24. 2 ( 1 + 0. 0004 × 1180)
R = 35. 62Ω
Current, I = V R
Current, I = 110/24.2 = 4. 5 A
Power delivered = I²R = (4.5)² × 35. 62 = 721.31 Watts
Thus, the power delivered to the coil is 721.31 Watts
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Answer:
Aceleración, a = 2 m/s²
Explanation:
Dados los siguientes datos;
Velocidad inicial = 108 km/h
Tiempo = 10 segundos
Velocidad final = 36 km/h
To find the average acceleration;
Conversión:
36 km/h to meters per seconds = 36*1000/3600 = 10 m/s
108 km/h to meters per seconds = 108*1000/3600 = 30 m/s
I. Para encontrar la aceleración, usaríamos la primera ecuación de movimiento;
Dónde;
V es la velocidad final.
U es la velocidad inicial.
a es la aceleración.
t es el tiempo medido en segundos.
Sustituyendo en la fórmula, tenemos;
Aceleración, a = 2 m/s²
Answer:
* Experiment with a higher range of materials
* Use a galvanometer.
* Vary in number of coils of the electromagnet
Explanation:
This is an experiment of electricity and magnetism, in general the best way to improve the results are:
* Experiment with a higher range of materials
allowing to know the scope of the initial assumptions
* Use a galvanometer.
The more accurate the readings the error of the derived quantities is the less which will improve the precision of the experiment.
* Vary in number of coils of the electromagnet
Since it allows to have greater magnetic fields and therefore expand the range of measurements
Answer:
Some examples of the uses of a screw are in a jar lid, a drill, a bolt, a light bulb, faucets, bottle caps and ball point pens.
Explanation:
