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3 years ago

What is momentum in physics?

Physics

2 answers:

Natali5045456 [20]3 years ago

8 0

P = mv

p = momentum

m = mass

v = velocity

Shalnov [3]3 years ago

7 0

Answer:

Explanation:

momentum = mass * velocity

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A water molecule consists of two hydrogen atoms bonded with one oxygen atom. The bond angle between the two hydrogen atoms is 10

Brut [27]

Explanation:

According to the figure,

$\vec{p} = q\vec{d}$

Formula to calculate net dipole moment is as follows.

$\vec{p_{net}} = 2P Cos 52^{o}\hat{i} + (0)\hat{j}$

$\vec{p_{net}} = 2qd Cos 52^{o}\hat{i}$

= $2 \times 1.6 \times 10^{-19} \times 0.958 \times 10^{-10} \times Cos 52^{o}\hat{i}$

= $1.88 \times 10^{-29}\hat{i}$ C-m

Therefore, we can conclude that the net dipole moment for given water molecule is $1.88 \times 10^{-29}\hat{i}$ C-m.

5 0

3 years ago

Can someone please answer this ? it doesn’t make sense to me

s344n2d4d5 [400]

Answer:

me too I can't understand

6 0

3 years ago

How much time is needed for a car to accelerate from 2.0 m/s to a speed of 6.0 m/s if its acceleration is 10 m/s^2

krok68 [10]

Answer:

I need help on dbq

Explanation:

3 0

2 years ago

How do you graph motion in physics? How do you graph motion in physics? I've seen problems state that an object is in free fall

Dahasolnce [82]

This is Kinematics and the equations in your book.

A speed time graph would plot the speed of something against the teime it was at a speed.

If it were changing it speed constantly, that would be a straight line if acclerating. Total distrance would be the area under the graph.

5 0

3 years ago

In a physics laboratory experiment, a coil with 200 turns enclosing an area of 13.1 cm2 is rotated during the time interval 3.10

sergij07 [2.7K]

Answer:

A) $\Phi=83.84\times 10^{-9}$

B) $\Phi=0 Wb$

C) $emf=5.4090\times 10^{-4}V$

Explanation:

Given that:

no. of turns i the coil, $n=200$

area of the coil, $a=13.1 \times 10^{-4}\,m^2$

time interval of rotation, $t=3.1\times 10^{-2}\,s$

intensity of magnetic field, $B=6.4\times 10^{-5}\,T$

(A)

Initially the coil area is perpendicular to the magnetic field.

So, magnetic flux is given as:

$\Phi=B.a\,cos \theta$ ..................................(1)

$\theta$ is the angle between the area vector and the magnetic field lines. Area vector is always perpendicular to the area given. In this case area vector is parallel to the magnetic field.

$\Phi=6.4\times 10^{-5}\times 13.1 \times 10^{-4}\, cos 0^{\circ}$

$\Phi=83.84\times 10^{-9} Wb$

(B)

In this case the plane area is parallel to the magnetic field i.e. the area vector is perpendicular to the magnetic field.

∴ $\theta=90^{\circ}$

From eq. (1)

$\Phi=6.4\times 10^{-5}\times 13.1 \times 10^{-4}\, cos 90^{\circ}$

$\Phi=0 Wb$

(C)

According to the Faraday's Law we have:

$emf=n\frac{B.a}{t}$

$emf=\frac{200\times 6.4\times 10^{-5}\times 13.1 \times 10^{-4}}{3.1\times 10^{-2}}$

$emf=5.4090\times 10^{-4}V$

7 0

3 years ago