For a point charge, how does the potential vary with distance from the point charge, r?
a constant
b. r.
c. 1/r.
d.
.
e.
.
Answer:
The correct option is C
Explanation:
Generally for a point charge the electric potential is mathematically represented as

Here we can deduce that the electric potential varies inversely with the distance i.e

So
Initial velocity(u) = 11.2 m/s.
Final velocity(v) = ?
acceleration(a) = 10.2 m/s²
Using kinematic equation v = u + at
v = 11.2 + 10 x 8 = 11.2 + 80 = 91.2 m/s.
Therefore final velocity is 91.2 m/s.
... power p supplied to a resistor whose resistance is r when it is known that it has a voltage δv across ... supplied to a resistor whose resistance
True
The more the number of shells will let go of their outer electrons more easily because the effective nuclear charge on the outer (valence) electrons will be lower. This is called 'shielding', the outer electrons will be shielded from the nucleus by the inner electrons.
Hope this Helps
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