(d) President McKinley did not want war.
Answer: 29.50 m
Explanation: In order to calculate the higher accelation to stop a train without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:
f=μ*N the friction force is equal to coefficient of static friction multiply the normal force (m*g).
f=m.a=μ*N= m*a= μ*m*g= m*a
then
a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2
With this value we can determine the short distance to stop the train
as follows:
x= vo*t- (a/2)* t^2
Vf=0= vo-a*t then t=vo/a
Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m
Answer:
960 m
Explanation:
Given that,
- Speed = 120 m/s
- Time taken = 4 minutes
We have to find the distance covered.
Firstly, let's convert time in seconds.
→ 1 minute = 60 seconds
→ 4 minutes = (4 × 60) seconds
→ 4 minutes = 240 seconds
Now, we know that,
→ Distance = Speed × Time
→ Distance = (4 × 240) m
→ Distance = 960 m
Therefore, distance covered is 960 m.
No work is done because the object needs to be moved. The formula for work is Work = Force x Distance.
