All categories

2 years ago

An object is 70 micrometer long and 47.66 micrometer wide. How long and wide is the object in km

Physics

1 answer:

MatroZZZ [7]2 years ago

7 0

Answer:

The length of the object in kilometer (km) is 70 x 10⁻⁹ km

The width of the object in kilometers (km) is 47.66 x 10⁻⁹ km

Explanation:

Given;

length of the object = 70 micrometer = 70 μm

the width of the object = 47.66 micrometer = 47.66 μm

The length of the object in meter:

70 micrometer = 70 μm = 70 x 10⁻⁶ m

The length of the object in kilometer (km):

70 x 10⁻⁶ m = 70 x 10⁻⁹ km

The width of the object in meters:

47.66 micrometer = 47.66 μm = 47.66 x 10⁻⁶ m

The width of the object in kilometers (km):

47.66 x 10⁻⁶ m = 47.66 x 10⁻⁹ km

You might be interested in

Auroras are frequently seen

Kipish [7]

Auroras are frequently seen : B. After solar flares
The Aurora is created by an ongoing influx of particles into the Earth's existing magnetic field,
This particles originated from the Sun as part of Solar wind

hope this helps

3 0

2 years ago

if you jump from a window that is 2 meters up you will most likely break the bones in your legs when you land however on a tramp

Gemiola [76]

<span>The de-acceleration or negative acceleration of stopping is what damages bones. The ground is rigid and therefore the change in momentum when striking the ground will be large. On the trampoline, the elasticity of the material means that the momentum changes more slowly, resulting in smaller accelerations.</span>

5 0

3 years ago

A mass moves back and forth in simple harmonic motion with amplitude A and period T.

Sever21 [200]

a. 0.5 T

- The amplitude A of a simple harmonic motion is the maximum displacement of the system with respect to the equilibrium position

- The period T is the time the system takes to complete one oscillation

During a full time period T, the mass on the spring oscillates back and forth, returning to its original position. This means that the total distance covered by the mass during a period T is 4 times the amplitude (4A), because the amplitude is just half the distance between the maximum and the minimum position, and during a time period the mass goes from the maximum to the minimum, and then back to the maximum.

So, the time t that the mass takes to move through a distance of 2 A can be found by using the proportion

$1 T : 4 A = t : 2 A$

and solving for t we find

$t=\frac{(1T)(2 A)}{4A}=0.5 T$

b. 1.25T

Now we want to know the time t that the mass takes to move through a total distance of 5 A. SInce we know that

- the mass takes a time of 1 T to cover a distance of 4A

we can set the following proportion:

$1 T : 4 A = t : 5 A$

And by solving for t, we find

$t=\frac{(1T)(5 A)}{4A}=\frac{5}{4} T=1.25 T$

6 0

2 years ago

Hannah just finished building a house of cards that stands four stories high. She is worried that it will fall down. Which of th

Tju [1.3M]

A.) <span>If no unbalanced force acts upon the house of cards, then it will remain standing forever.

[ Other Statements doesn't make any sense in Physics, they can be true in some situation & can't be false, option A is the only answer ]
Hope this helps!</span>

6 0

3 years ago

Read 2 more answers

Which descriptions best fit the labels? X: kinetic energy Y: potential energy X: potential energy Y: kinetic energy X: mechanica

GalinKa [24]

its the 3rd option!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

4 0

3 years ago

Read 2 more answers