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mart [117]
2 years ago
5

A bartender slides a beer mug at 1.3 m/s towards a customer at the end of a frictionless bar that is 1.3 m tall. The customer ma

kes a grab for the mug and misses, and the mug sails off the end of the bar. (a) How far away from the end of the bar does the mug hit the floor
Physics
1 answer:
sineoko [7]2 years ago
6 0

Answer:

x = 0.67 m

Explanation:

For this problem, let's use the projectile launch equations, as the jug goes through the bar, it comes out with horizontal speed vx = 1.3 m / s, which does not decrease as there is no friction.

Let's find the time or it takes to get to the floor

          y = y₀ + v_{oy} - ½ g t²

in this case I go = 0 and when I get to the floor y = 0

         0 = y₀ + 0 - ½ g t²

          t² = 2y₀ / g

          t² = 2 1.3 / 9.8 = 0.2653

          t = 0.515 s

now let's find the distance traveled in this time

         x = vx t

         x = 1.3  0.515

         x = 0.6696 m

         x = 0.67 m

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valina [46]

a. The spring is compressed  by  0.174 m.

b.  The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.

c. The horizontal velocity of the dart at that time is  13.74 m/s.

d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.

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b. Given is a 0.010 kg dart is fired straight up.

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d.  Time that dart spends in air, t = √2h/g

t = √(2x9.6)/9.81

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The horizontal distance from the equilibrium position at which the dart hits the ground.

Horizontal distance = (Velocity on x direction) x time

Horizontal distance = 13.74 m/s x 1.4s

Horizontal distance = 19.236 m

Thus, the horizontal distance is 19.236 m.

Learn more about potential energy.

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