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mart [117]
3 years ago
5

A bartender slides a beer mug at 1.3 m/s towards a customer at the end of a frictionless bar that is 1.3 m tall. The customer ma

kes a grab for the mug and misses, and the mug sails off the end of the bar. (a) How far away from the end of the bar does the mug hit the floor
Physics
1 answer:
sineoko [7]3 years ago
6 0

Answer:

x = 0.67 m

Explanation:

For this problem, let's use the projectile launch equations, as the jug goes through the bar, it comes out with horizontal speed vx = 1.3 m / s, which does not decrease as there is no friction.

Let's find the time or it takes to get to the floor

          y = y₀ + v_{oy} - ½ g t²

in this case I go = 0 and when I get to the floor y = 0

         0 = y₀ + 0 - ½ g t²

          t² = 2y₀ / g

          t² = 2 1.3 / 9.8 = 0.2653

          t = 0.515 s

now let's find the distance traveled in this time

         x = vx t

         x = 1.3  0.515

         x = 0.6696 m

         x = 0.67 m

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Answer:

Distance covered is: 45 meters

Displacement is 15 meters to the right of where he started

Explanation:

Notice that Brady has walk a path that looks like an incomplete rectangle of height 5 meters and length 25meters, although he actually didn't cover the full length (25 meters) when getting back to the point where he started (he made just 10 meters instead of 25 after the third turn right) See attached image.

Therefore, Brady's displacement is 15 meters to the right of where he started, and the total distance he covered is :

Distance = 5m + 25m + 5m + 10m = 45m

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