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cupoosta [38]
3 years ago
11

Please help me and explanation would be really awesome thank you!

Chemistry
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

So the answer would be 10 moles

Explanation:

1) Start with the molecular formula for water: H_{2} O!

2) If there are 10 moles of water use a mole ratio to calculate the moles of oxygen it would produce.

(This question is... interesting... since they chose an element that is diatomic in free state so It could TECHNICALLY be two answers, moles of O or moles of O_{2})

The mole ratio is 1 moles of H_{2}O to 1 moles of O. This is because the coefficient for oxygen in water is simple 1, so the ratio is 1:1.

3) that means if 10 moles of water decompose, they decompose into 10 moles of H_{2} and 10 moles of O.

Extra:

About what I was saying before about the question being slightly interesting:

10 moles of pure oxygen is produced but free state oxygen exists as O_{2} so it could possibly be 10 OR 5! However, notice it says elements. This leads me to believe the answer is 10 (monatomic oxygen) instead of 5 (free state/diatomic oxygen).

I hope this helps!

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Answer:

1. First one is true : as per periodic table down the group , the elements has increasing order of shell & with that the London dispersion forces brings the inter-molecules close together and bromine converted into liquid .

2. second one is False  because carbon-carbon bonds are not weak bonds they form mutual covalent bonds which are stronger bonds and cannot be easily disrupted .

3. A single carbon atom has the valency of 4 so it can be bonded with four hydrogen atom at the same time .

Explanation:

5 0
3 years ago
Which describes the elements in a given group of the periodic table?
victus00 [196]
C is the answer I think
3 0
3 years ago
What are the 7 methods of separating mixtures?​
Gennadij [26K]

Methods Of Separating Mixtures

Handpicking.

Threshing.

Winnowing.

Sieving.

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3 0
3 years ago
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How many moles of O2 are needed to react with 2.35 mol of C2H2?
Mrrafil [7]
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

2.35 mol C2H2 - x mol O2
2 mol C2H2 - 5 mol O2

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5 0
4 years ago
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Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re
bearhunter [10]

Answer:  28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles

The balanced chemical equuation is:

4Al+3O_2\rightarrow 2Al_2O_3  

According to stoichiometry :

4 moles of Al produce == 2 moles of Al_2O_3

Thus 0.556 moles of Al will produce=\frac{2}{4}\times 0.556=0.278moles  of Al_2O_3

Mass of Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.

7 0
3 years ago
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