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3 years ago

If 50.75 g of a gas occupies 10.0 l at stp, 129.3 g of the gas will occupy __________ l at stp.

2 answers:

6 0

Use PV = mRT/M and solve for R. R = PVM/RT. Since you have the same gas under two sets of conditions then you can write
P1V1M1/m1T1 = P2V2M2/m2T2 
Since P, M and T are constant, the equation becomes 
V1/m1 = V2/m2 
Now plug in your values and solve for V2

Semenov [28]3 years ago

4 0

Answer: 25.5 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

We are given:

50.75 g of a gas occupies = 10.0 L at STP

Thus 129.3 g of a gas occupies = $\frac{10}{50.75}\times 129.3=25.5L$ at STP

Thus 129.3 g of gas will occupy 25.5 L at STP.

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How many atoms are there in 7.2 mol neon?

rosijanka [135]

Answer:

A) 4.3 × 10²⁴ atoms

Explanation:

Step 1: Given data

Moles of neon: 7.2 moles

Step 2: Calculate the number of atoms present in 7.2 moles of neon

In order to convert moles to toms, we need a conversion factor. In this case, we will use Avogadro's number: there are 6.02 × 10²³ neon atoms in 1 mole of neon atoms.

7.2 mol × 6.02 × 10²³ atoms/mol = 4.3 × 10²⁴ atoms

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2 years ago

ammonia gas is used as refrigerant 0.474 atm. Pressure is required to change 2000 cm3 sample of ammonia initially at 1.0 atm to

Andreas93 [3]

Answer: The pressure required is 0.474 atm

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}V}$ (At constant temperature and number of moles)

The equation is,

${P_1V_1}={P_2V_2}$

where,

$P_1$ = initial pressure of gas = 1.0 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = $2000cm^3$

$V_2$ = final volume of gas = $4.22dm^3=4220cm^3$ ( $1dm^3=1000cm^3)$

Now put all the given values in the above equation, we get:

${1.0\times 2000}={P_2\times 4200}$

$P_2=0.474atm$

The pressure required is 0.474 atm

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2 years ago

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Answer:

The resulting structure is:

R-CH-CH2 (OH)-CH-CH2(OH)-CH-CH2(OH)-CH-...

Explanation:

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