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Triss [41]
2 years ago
6

Which electromagnetic waves have the shortest wavelengths and highest frequencies?

Physics
2 answers:
eduard2 years ago
6 0
The correct answer is A. Gamma Rays.  They have the shortest wave-length, and the highest frequency.  

Hope I helped.  :)
Usimov [2.4K]2 years ago
3 0

Answer: Gamma rays

Explanation: The given waves belong to the electromagnetic spectrum which consists of different electromagnetic radiations arranged in terms of increasing wavelengths or decreasing frequencies.

E= h\times \nu

\nu=\frac{c}{\lambda}

Thus E=\frac{h\times c}{\lambda}

E= energy

\nu= frequency

c = speed of light

\lambda = wavelength

Thus frequency and wavelength are inversely related. The waves having high energies ave high frequencies and have shorter wavelengths.

Thus gamma rays having highest energy have highest frequency and shortest wavelength.


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As a pelican flies through the air, it flaps its wings, thereby pushing down on the air below. What is the reaction force?
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the reaction force in this situation would be B

Explanation:

The action is the wings pushing down whilst the reaction is the air pushing up which allow the bird to fly .

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Which of the following results when a crest and trough meet?
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D. Destructive interference. An easy way to think about it is the waves are opposite each other, so they essentially cancel each other out, or make an effort to.
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At t=0 bullet A is fired vertically with an initial (muzzle) velocity of 450 m/s. When 3s. bullet B is fired upward with a muzzl
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Answer:

At time 10.28 s after A is fired bullet B passes A.

Passing of B occurs at 4108.31 height.

Explanation:

Let h be the height at which this occurs and t be the time after second bullet fires.

Distance traveled by first bullet can be calculated using equation of motion

s=ut+0.5at^2 \\

Here s = h,u = 450m/s a = -g and t = t+3

Substituting

h=450(t+3)-0.5\times 9.81\times (t+3)^2=450t+1350-4.9t^2-29.4t-44.1\\\\h=420.6t-4.9t^2+1305.9

Distance traveled by second bullet

Here s = h,u = 600m/s a = -g and t = t

Substituting

h=600t-0.5\times 9.81\times t^2=600t-4.9t^2\\\\h=600t-4.9t^2 \\

Solving both equations

600t-4.9t^2=420.6t-4.9t^2+1305.9\\\\179.4t=1305.9\\\\t=7.28s \\

So at time 10.28 s after A is fired bullet B passes A.

Height at t = 7.28 s

h=600\times 7.28-4.9\times 7.28^2\\\\h=4108.31m \\

Passing of B occurs at 4108.31 height.

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3 years ago
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s344n2d4d5 [400]

Answer:

False

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