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Triss [41]
3 years ago
6

Which electromagnetic waves have the shortest wavelengths and highest frequencies?

Physics
2 answers:
eduard3 years ago
6 0
The correct answer is A. Gamma Rays.  They have the shortest wave-length, and the highest frequency.  

Hope I helped.  :)
Usimov [2.4K]3 years ago
3 0

Answer: Gamma rays

Explanation: The given waves belong to the electromagnetic spectrum which consists of different electromagnetic radiations arranged in terms of increasing wavelengths or decreasing frequencies.

E= h\times \nu

\nu=\frac{c}{\lambda}

Thus E=\frac{h\times c}{\lambda}

E= energy

\nu= frequency

c = speed of light

\lambda = wavelength

Thus frequency and wavelength are inversely related. The waves having high energies ave high frequencies and have shorter wavelengths.

Thus gamma rays having highest energy have highest frequency and shortest wavelength.


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Nageen's motor power: W_N = F x S / T = F x 0.35 / 1.8 = 0.194F

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Consider a heat pump that operates on the reversed Carnot cycle with R-134a as the working fluid executed under the saturation d
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Work out = 28.27 kJ/kg

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h_{fg} = 171.82 kJ/kg

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T_{L} = -18.77°C = 254.23 K

At saturation pressure  800 kPa, the saturation temperature is

T_{H} = 31.31°C = 304.31 K

Now heat rejected will be same as enthalpy during vaporization since heat is rejected from saturated vapour state to saturated liquid state.

Thus, q_{reject} = h_{fg} = 171.82 kJ/kg

We know COP of heat pump

COP = \frac{T_{H}}{T_{H}-T_{L}}

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Therefore, Work out put, W = \frac{q_{reject}}{COP}

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8 0
3 years ago
Two mass m1 and m2 lie on a frictionless surface. Between the two masses is a compressed spring, with spring constant k. The sys
max2010maxim [7]

Answer:

The spring was compressed the following amount:

\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }

Explanation:

Use conservation of energy between initial and final state, considering that the surface id frictionless, and there is no loss in thermal energy due to friction. the total initial energy is the potential energy of the compressed spring (by an amount \Delta x), and the total final energy is the addition of the kinetic energies of both masses:

E_i=\frac{1}{2} k\,(\Delta x)^2\\\\E_f=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2

E_i=E_f\\

\frac{1}{2} k\,(\Delta x)^2=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2\\k\,(\Delta x)^2=m_1\,v_1^2+ m_2\,v_2^2\\(\Delta x)^2=\frac{m_1\,v_1^2+ m_2\,v_2^2}{k} \\\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }

8 0
3 years ago
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