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m_a_m_a [10]
3 years ago
13

Which wavelength of the electromagnetic spectrum are shorter than visible light and carry more energy

Physics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

C

Explanation:

Which wavelength of the electromagnetic spectrum are shorter than visible light and carry more energy

A micro

B radio

C ultraviolet

F infrared

The correct answer is C

The visible light wavelength is of 7 × 10^-7 m while the ultraviolet is of other

4 × 10^-8 m

Therefore, ultravolet is shorter than visible light and carry more energy

Therefore, the correct answer is option C.

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How does self efficacy relate to sports performance?
vitfil [10]

Answer: Individuals with high self efficacy will participate readily and more frequently, will put more effort in and persist longer, enhancing performance in sport and exercise

6 0
2 years ago
Sophia is planning on going down an 8-m water slide. Her weight is 50 N. She knows that she has gravitational potential energy (
RideAnS [48]

Answer:

Explanation:

graph would be a straight line from (0, 0) to (400, 8)

Plot points are

PE = mgh

50(0) = 0 J

50(2) = 100 J

50(4) = 200 J

50(6) = 300 J

50(8) = 400 J

4 0
3 years ago
Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.0*109 V and the quantity of charg
nata0808 [166]

Answer:

a) U_{e} = 3 \times 10^{10}\,J, b) v \approx 7745.967\,\frac{m}{s}

Explanation:

a) The potential energy is:

U_{e} = Q \cdot \Delta V

U_{e} = (30\,C)\cdot (1.0\times 10^{9}\,V)

U_{e} = 3 \times 10^{10}\,J

b) Maximum final speed:

U_{e} = \frac{1}{2}\cdot m \cdot v^{2}\\v = \sqrt{\frac{2\cdot U_{e}}{m} }

The final speed is:

v=\sqrt{\frac{2\cdot (3 \times 10^{10}\,J)}{1000\,kg} }

v \approx 7745.967\,\frac{m}{s}

3 0
3 years ago
Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the
erma4kov [3.2K]

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

7 0
3 years ago
Read 2 more answers
Select the correct answer.
Serhud [2]

Answer:

b hope this helps

Explanation:

5 0
3 years ago
Read 2 more answers
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