Using the velocity-time graph, the displacement can be calculated by the area under the velocity-time graph. At 3 seconds the total displacement is then equal to (4)(2) + (4 + 2)*1/2 = 11 m. Assuming that the starting point is at x = 0, then the particle at t=3s is at x=11 m.
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Answer:
casa. Completa las oraciones con el pronombre de objeto directo correcto, según el contexto.
1. Tu ropa está sucia. ¿Por qué no ____ lavas?
2. Ellos tienen muchos libros. ____ tienen en la estantería del despacho.
3. La casa de mi mamá tiene muchas ventanas, pero no ______ abre todos los días.
4. Profesora, Ud. debe usar la cochera. ¿ ______ve allí?
5. ¿Quieres ir al cine con nosotros? _____ llamamos antes de salir.
Answer:
The shearing stress is 10208.3333 Pa
The shearing strain is 0.25
The shear modulus is 40833.3332 Pa
Explanation:
Given:
Block of gelatin of 120 mm x 120 mm by 40 mm
F = force = 49 N
Displacement = 10 mm
Questions: Find the shear modulus, Sm = ?, shearing stress, Ss = ?, shearing strain, SS = ?
The shearing stress is defined as the force applied to the block over the projected area, first, it is necessary to calculate the area:
A = 40*120 = 4800 mm² = 0.0048 m²
The shearing stress:
The shearing strain is defined as the tangent of the displacement that the block over its length:
Finally, the shear modulus is the division of the shearing stress over the shearing strain:
Answer:
we could use the formula, v=u+at,
65=25+a (10), a=4 , since the motion is declerating we have a=-4 m/s2
Answer:
If we use the equation for the transformation of velocities for moving frames:
v' = (v - u) / (1 - u * v / c^2) where we measure the speed of v' approaching from the left where v is in a frame moving at -u towards v'
v' = (.6 c - (-.6 c)) / (1 - (-.6 c) * .6 c / c^2) = 1.2 c / (1 + .6 * .6)
or v' = 1.2 c / (1 + .36) = .88 c
v is approaching from the left at .6 c in the reference frame and the other frame approaches from the right at -.6 c with speed u (-.6 c) and we measure the speed of v as seen in the frame moving to the left
