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Viefleur [7K]
3 years ago
6

"When the ball leaves the ramp at Point B, students measure the horizontal" distance traveled. They repeat the experiment five t

imes, being careful to release the ball from the same starting Point A and find the average horizontal distance traveled to be 2.0 m. One student suggests they use a stopwatch to find the time the ball is in the air whereas another student suggests they use a meter stick. Given these materials, describe the procedure students should follow to minimize error and calculate the speed of the ball as it leaves the ramp.
Physics
1 answer:
romanna [79]3 years ago
6 0

Answer:

Speed of ball as it leaves ramp is 2 m/s

Explanation:

From the question it is given that the average distance traveled by ball from point A to B is 2.0 m and the time taken is 1sec

one student is using stopwatch to calculate the time taken by ball and another student is using meter stick to calculate the distance traveled

since speed of ball is given by v = \frac{distance}{time}  thus,

the speed = 2 m/s

now for minimizing the error of speed it is necessary to record the readings by single students at-least 5 times and take average

by doing this, the error of speed calculation will be minimum as the it decreases the error due to random error of system caused by taking the reading  by different students

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Why do you think people translate sound waves from compression waves to transverse waves ?
gladu [14]

Answer:

Sound waves are translated into transverse waves to know the frequency, amplitude, wavelength etc of the waves.

Explanation:

They translate the sound waves to know the depth about that specific waves and translating it to transverse waves makes it easier.

Hope it helps :D

8 0
3 years ago
Difference between constant speed and average speed
Tresset [83]
If a body is traveling with constant speed , it means that it's distance is constantly increasing with time.

If it goes 5m in 3min , it will go 5m in next 3 min.

Average velocity is the total displacement divided by total time.

When the body travels 5m in 3 min and 25 m in next 3min , average velocity
=(25+5)/(3+3)
=30/6
=5m/min
8 0
3 years ago
What is the electric field 3.9 m from the center of the terminal of a Van de Graaff with a 6.60 mC charge, noting that the field
earnstyle [38]

Answer:

the electric field is  3.91 x 10⁶ N/C

Explanation:

Given the data in the question;

Electric field at a point due to point charge is;

E = kq/r²

where k is the constant, r is the distance from centre of terminal to point where electric field is, q is the excess charge placed on the centre of terminal of Van de Graff,a generator

Now, given that r = 3.9 m, k = 9.0 x 10⁹ Nm²/C², q = 6.60 mC = 6.60 x 10⁻³ C

so we substitute into the formula

E = [(9.0 x 10⁹ Nm²/C²)( 6.60 x 10⁻³ C)] / ( 3.9 )²

E = 59400000 / 15.21

E = 3.91 x 10⁶ N/C

Therefore, the electric field is  3.91 x 10⁶ N/C

3 0
3 years ago
You walk to school every day. It is 0.5 miles. After school you walk to Kroger, which is 1.3 miles. You leave Kroger to go all b
marin [14]
The total distance you haved walked should be 2.6 miles
7 0
3 years ago
A roller-coaster car has a mass of 1240 kg when fully loaded with passengers. As the car passes over the top of a circular hill
LiRa [457]

Answer:

a)      N = 7.90 10³ N,  b) N = -1.04 10⁴ N

Explanation:

a) For this exercise we can use Newton's second law

             N -W = m (-a)

The relationship is centripetal, the negative sign of the acceleration is because it points towards the center of the circle

              a = v² / r

we substitute

             N = mg -m v² /r  

             N = m (g - v² /r)

let's calculate

v = 8.7 m / s

             N = 1240 (9.81 - 8.7²/22)

             N = 7.90 10³ N

b) v = 20 m / s

             N = 1240 (9.81 - 20²/22)

             N = -1.04 10⁴ N

8 0
3 years ago
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