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3 years ago

14

An object has a kinetic energy of 268 j and a momentum of magnitude 22.4 kg·m/s. find the speed and the mass of the object.

1 answer:

Hoochie [10]3 years ago

8 0

Rearrange equation 2:
m = 20.3/v
Sub into equation 1:
466 = (20.3/v)v^2
466 = 20.3v
v = 466 / 20.3
v = 22.96 m/s
Use to find m:
m = 20.3 / 22.96
m = 0.8843 kg
Rounding:
v = 23.0 m/s to three significant figures.
m = 0.884 kg to three significant figures.

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Recall specific heat of water is 4186 j/kg/C. Find the specific heat of sample.

Paraphin [41]

Answer:

Shown by explanation;

Explanation:

The heat of the sample = mass ×specific heat capacity of the sample × temperature change(∆T)

Assumption;I assume the mass of the samples are : 109g and 192g

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For 0.192g are;

∆T= 67-30.1-=36.9°c

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3 years ago

The student makes a single pile of the 500 sheets of paper. Which a metre rule, she measured the height of the pile. The height

Cerrena [4.2K]

Answer: please see attached work.

Explanation: please see attached work. Assuming 500 sheets of paper = 20 lb. (typicical value).

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3 years ago

A 57 kg wagon is pulled with a constant net force of 38 N. Calculate the acceleration of the wagon. F = ma

Dahasolnce [82]

Answer:

<h2>0.67 m/s²</h2>

Explanation:

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$a = \frac{f}{m} \\$

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m is the mass

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We have the final answer as

<h3>0.67 m/s²</h3>

Hope this helps you

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2 years ago

If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?

steposvetlana [31]

Hi there!

$\large\boxed{\text{B) 20 meters}}$

We know that:

$E_T = U + K$

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K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

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<u>h = 20 meters</u>

3 0

2 years ago

Two identical conducting spheres, A and B, carry equal charge. They are separated by a distance much larger than their diameters

Vesnalui [34]

Answer:

C. $\frac{3F}{8}$

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When the sphere C is touched by A, the final charges on both will be, $\frac{q}{2}$

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Now the force between A and B is calculated as:

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Hence the electrostatic force becomes 3F/8

4 0

2 years ago