1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lorico [155]
3 years ago
9

Is sliver or aluminum most often used in magnets

Chemistry
1 answer:
dedylja [7]3 years ago
6 0
Neither of them are used in magnets they don’t attract metal
You might be interested in
In one kind of nuclear reaction, two nuclei fuse, or join together, to form a larger nucleus. This kind of reaction happens only
Vladimir79 [104]
High pressures are necessary to create such reaction so that the particles will be able to overcome electrostatic repulsion. The particles that make up a particular atom are covered by shells of energy that react to different impulses like pressure. When particles are exposed to extreme environmental pressure it has the tendency to split its particles and undergo nuclear fusion successfully.
7 0
3 years ago
On a summer day early in the moming, a balloon is filled with helium when the temperature
MAXImum [283]

Based on the data provided;

  • number of moles of helium gas is 1.25 moles
  • pressure at peak temperature is 259.3 kPa
  • internal pressure is above 256 kPa, therefore, the balloon will burst.
  • pressure should be reduced to a value less than 256 kPa by reducing the temperature

<h3>What is the ideal has equation?</h3>

The ideal gas equation relatesthe pressure, volume, moles and temperature of a gas.

The moles of helium gas is calculated using the Ideal gas equation:

  • PV = nRT

n is the number of moles of gas

R is molar gas constant = 8.314 L⋅kPa/Kmol

P is pressure = 239 kPa

T is temperature = 21°C = 294 K

V is volume = 12.8 L

Therefore;

n = PV/RT

n = 239 × 12.8 / 8.314 × 294

n = 1.25 moles

The number of moles of helium gas is 1.25 moles

At peak temperature, T = 46°C = 319 K

Using P1/T1 = P2/T2

P2 = P1T2/T1

P2 = 239 × 319/294

P2 = 259.3 kPa

The pressure at peak temperature is 259.3 kPa

At 42°C, T = 315 K

Using P1/T1 = P2/T2

P2 = P1T2/T1

P2 = 239 × 315/294

P2 = 256.07 kPa

Since the internal pressure is above 256 kPa, the balloon will burst.

The pressure should be reduced to a value less than 256 kPa by reducing the temperature.

Learn more about gas ideal gas equation at: brainly.com/question/12873752

6 0
2 years ago
Which is a FALSE statement about the possible benefits of nanocars? A. They could work together to build really complex things.
kondor19780726 [428]
C, they could work together to make things from the top down. 
6 0
3 years ago
Think of a bath sponge. What happens when you squeeze it? How could you explain it from the point of view of the state of the ag
harkovskaia [24]

Answer:

What happens when it is squeezed is that its volume increases, the pressure of the material increases.

Explanation:

This is due to the fact that the elastic modulus of the sponge is high and withstands broad forces without deforming its structure, since the force is made within the proportional limit of its particles without modifying or permanently deforming them, that is why when stopping doing pressure or force on it its shape returns to being the original, this also happens due to the phenomenon of resilience

3 0
3 years ago
A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C・g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('
polet [3.4K]

Answer:

a=5.65cm

Explanation:

Hello,

In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:

Q_{Pt}=-Q_{Deu}

We can represent the heats in terms of mass, heat capacities and temperatures:

m_{Pt}Cp_{Pt}(T_f-T_{Pt})=-m_{Deu}Cp_{Deu}(T_f-T_{Deu})

Thus, we solve for the mass of platinum:

m_{Pt}=\frac{-m_{Deu}Cp_{Deu}(T_f-T_{Deu})}{Cp_{Pt}(T_f-T_{Pt})} \\\\m_{Pt}=\frac{-1.00L*1110g/L*4.211J/(g\°C)*(41.9-25.5)\°C}{0.1256J/(g\°C)*(41.9-200.0)\°C} \\\\m_{Pt}=3860.4g

Next, by using the density of platinum we compute the volume:

V_{Pt}=\frac{3860.4g}{21.45g/cm^3}\\ \\V_{Pt}=180cm^3

Which computed in terms of the edge length is:

V=a^3

Therefore, the edge length turns out:

a=\sqrt[3]{180cm^3}\\ \\a=5.65cm

Best regards.

6 0
3 years ago
Other questions:
  • List 10 examples of substances that are beneficial in small quantities but poisonous in large doses
    10·2 answers
  • Which of the following atoms:
    15·1 answer
  • Draw the Lewis structure of H2O. Include any nonbonding electron pairs. Draw the molecule by placing atoms on the grid and conne
    7·1 answer
  • A storage tank contains nitrogen, oxygen, and carbon dioxide. The partial pressure of nitrogen is 0.79 ATM and Oxygen is 0.19 AT
    8·1 answer
  • Need help please!!!!!!!
    6·2 answers
  • I am using a graduated cylinder to measure the volume of my keys . Before I place the keys in , the volume is 35mL. After I plac
    10·1 answer
  • What are the 7 sources of energy?
    8·1 answer
  • The setup in the diagram is left outside during the day and night . Bubbles are continuously produced regardless of the presence
    7·1 answer
  • The electronegativity values of carbon, hydrogen, and nitrogen are compared in the table.
    7·1 answer
  • How much sugar can be dissolved of the 0.3 ml of water is heated to 1000C?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!