Question

How many grams of NaCl do you need to prepare 200 ml of a 5M solution? The molecular weight of NaCl is 58.4 g/mol. Smol 0.2L-1mol NaCl lib Imol NaClx 8.glol Nacl Mol 58.19 Nac

Answer 1

Answer:

The answer to your question is: 58.4 g of NaCl

Explanation:

Data

Volume = 200 ml = 0.2 l

Concentration = 5M

MW = 58.4 g

mass NaCl = ?

Formula

             Molarity = (# of moles ) / volume

             # of moles = Molarity x volume

             # of moles = 5 x 0.2

             # of moles = 1

              58.4 g ---------------------- 1 mol

              x          ---------------------  1 mol

              x = (1 x 58.4) / 1

             x = 58.4 g of NaCl