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3 years ago

HELP ASAP! GIVING BRAINLIEST!! How could you give a pendulum more energy?

Chemistry

1 answer:

Virty [35]3 years ago

5 0

Answer:

Explanation:

In a simple pendulum with no friction, mechanical energy is conserved. Total mechanical energy is a combination of kinetic energy and gravitational potential energy. As the pendulum swings back and forth, there is a constant exchange between kinetic energy and gravitational potential energy

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What is biochemistry

lana66690 [7]

Answer:

Branch of science concerned with the chemical and physicochemical processes and substances that occur within living organisms.

7 0

2 years ago

How many grams of Ca(NO3)2 are needed to make 25.0 g of a 15.0% Ca(NO3)2(aq)?

yarga [219]

Answer:

3.75 g.

Explanation:

mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.

mass % = (mass of solute/mass of solution) x 100.

mass of calcium nitrite = ??? g,

mass of the solution = 25.0 g.

∴ mass % = (mass of solute/mass of solution) x 100

∴ mass of solute (calcium nitrite) = (mass %)(mass of solution)/100 = (15.0 %)(25.0 g)/100 = 3.75 g.

5 0

3 years ago

g a solution is made by mixing 500.0 mL of 0.037980.03798 M Na2sO4 Na2sO4 with 500.0 mL of 0.034280.03428 M NaOH NaOH . Complete

Mandarinka [93]

Answer:

The concentration of the sodium and arsenate ions at the end of the reaction in the final solution

[Na⁺] = 0.05512 M

[HAsO₄²⁻] = 0.00185 M

[AsO₄³⁻] = 0.01714 M

Explanation:

Complete Question

A solution is made by 500.0 mL of 0.03798 M Na₂HAsO₄ with 500.0 mL of 0.03428 M NaOH. Complete the mass balance expressions for the sodium and arsenate species in the final solution.

Na₂HAsO₄ + NaOH → Na₃AsO₄ + H₂O

From the information provided in this question, we can calculate the number of moles of each reactant at the start of the reaction and we then determine which reagent is in excess and which one is the limiting reagent (in short supply and determines the amount of products to be formed)

Concentration in mol/L = (Number of moles) ÷ (Volume in L)

Number of moles = (Concentration in mol/L) × (Number of moles)

For Na₂HAsO₄

Concentration in mol/L = 0.03798 M

Volume in L = (500/1000) = 0.50 L

Number of moles = 0.03798 × 0.5 = 0.01899 mole

For NaOH

Concentration in mol/L = 0.03428 M

Volume in L = (500/1000) = 0.50 L

Number of moles = 0.03428 × 0.5 = 0.01714 mole

Since the NaOH is in short supply, it is evident that it is the limiting reagent and Na₂HAsO₄ is in excess.

Na₂HAsO₄ + NaOH → Na₃AsO₄ + H₂O

0.01899 0.01714 0 0 (At time t=0)

(0.01899 - 0.1714) | 0 → 0.01714 0.01714 (end)

0.00185 | 0 → 0.01714 0.01714 (end)

Hence, at the end of the reaction, the following compounds have the following number of moles

Na₂HAsO₄ = 0.00185 mole

This means Na⁺ has (2×0.00185) = 0.0037 mole at the end of the reaction and (HAsO₄)²⁻ has 0.00185 mole at the end of the reaction

NaOH = 0 mole

Na₃AsO₄ = 0.01714 moles

This means Na⁺ has (3×0.01714) = 0.05142 mole at the end of the reaction and (AsO₄)³⁻ has 0.01714 mole at the end of the reaction

H₂O = 0.01714 moles

So, at the end of the reaction

Na⁺ has 0.0037 + 0.05142 = 0.05512 mole

(HAsO₄)²⁻ has 0.00185 mole

(AsO₄)³⁻ has 0.01714 mole.

And since the Total volume of the reaction setup is now 500 mL + 500 mL = 1000 mL = 1 L

Hence, the concentration of the sodium and arsenate ions at the end of the reaction is

[Na⁺] = 0.05512 M

[HAsO₄²⁻] = 0.00185 M

[AsO₄³⁻] = 0.01714 M

Hope this Helps!!!

8 0

3 years ago

Read 2 more answers

If you flow a solution of Mg CO3-- in water over a Cation resin, what will be in the outlet stream leaving the bed

vodka [1.7K]

In a a cation-exchange resin, the outlet stream leaving the bed will contain $H^{+}$ and $CO_3 ^{2-}$ .

<h3>What is cation-exchange resin?</h3>

A resin or polymer that serves as a medium for ion exchange is known as an ion-exchange resin or cation-exchange resin.
It is an insoluble matrix (or support structure) made from an organic polymer substrate, typically appearing as tiny (0.25-1.43 mm radius) microbeads that are white or yellowish in color.
The process is known as cation-exchange resin because the beads are often porous, providing a wide surface area on and inside them where the trapping of ions takes place along with the concomitant release of other ions.
cation-exchange resin comes in many different varieties. Polystyrene sulfonate is the main ingredient in most commercial resins. Many diverse separation, purification, and decontamination techniques use cation-exchange resin.
The most typical examples are water filtration and water softening.

To learn more about cation-exchange resin with the given link

brainly.com/question/21052225

#SPJ4

8 0

2 years ago

A compound with a molar mass of 100.0 g/lol has an elemental composition of 24.0% C, 3.0% H, 16.0% O and 57.0%F. What is the mol

ch4aika [34]

If I made no mistake in calculation, the given answer must be correct...(tried my best)

elements   :                       carbon     hydrogen    oxygen       Fluorine

composition [C]                     24           3                16                57

M r                                          12             1                16                19

(divide C by Mr)                       2               3                 1                  3

(Divide by smallest value)       2                3                  1                  3

(smallest value = 1...so all value remained constant)

Empirical formula : C2H3OF3

if molar mas = 100 g per mole, then

first step calculate Mr. of empirical formula: [= 100]

Them molecular formula = empirical formula

7 0

3 years ago