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belka [17]
4 years ago
12

Assume that speed = 10 and miles = 5. What is the value of each of the following expressions? a. speed + 12 – miles * 2 b. speed

+ miles * 3 c. (speed + miles) * 3 d. speed + speed * miles + miles e. (10 – speed) + miles / miles
Physics
1 answer:
Sergio [31]4 years ago
6 0

Explanation:

Speed = 10 and miles = 5

(a) Speed + 12 – miles * 2

10 + 12 - 5 × 2

= 12

(b) speed + miles × 3

10 + 5 × 3

= 25

(c) (speed + miles) × 3

(10 + 5) × 3

= 45

(d) speed + speed × miles + miles

10 + 10 × 5 + 5

= 65

(e) (10 – speed) + miles / miles

(10 - 10) + 5/5

= 1

Therefore, this is the required solution.

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8 0
3 years ago
A 68 kg person runs off a dock at 2.79 m/s and lands on a stationary 131 kg boat. What is their joint velocity afterward?
kolbaska11 [484]
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4 0
3 years ago
The following position vs time graph shows the motion of an object along its path from -10 to seconds. Based on this graph, what
Marrrta [24]

∆x (displacement) = v - u

where, v is the final position and u is the initial position.

Given, the final position of the object is 0 m and the initial position is 5 m.

∆x (displacement) = v - u

= 0 m - 5 m

= -5 m

Therefore, <u>C: -5m</u> is the correct answer.

6 0
3 years ago
#86 can an object be moving when its acceleration is zero? can an object be accelerating when its speed is zero?
liraira [26]
Yes, an object<span> that was set in motion in the past by some force, but that is no longer being acted on by a net force, is </span>moving<span> but with </span>zero acceleration<span>, i.e. it is </span>moving<span> at constant velocity.</span>
7 0
3 years ago
Cumulative Problem 1
Marrrta [24]

Answer:

Volume, V=696.55\ \mu m^3

Explanation:

Given that,

The diameter of a human cell is 11 μm

It is enclosed by a membrane that is 4,4 nm thick.

We need to find the volume of the cell. The cell is spherical in shape. The volume of a sphere is given by the formula as follows :

V=\dfrac{4}{3}\pi r^3

r is the radius of the sphere, r = 5.5 μm

So,

V=\dfrac{4}{3}\times 3.14\times (5.5)^3\\\\V=696.55\ \mu m^3

So, the volume of the cell is 696.55\ \mu m^3.

5 0
3 years ago
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