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3 years ago

Is the hand grip test an example of an isometric or an isotonic muscle contraction? Explain your reasoning.

Physics

1 answer:

shusha [124]3 years ago

5 0

Hand grip test an example of an isometric muscle contraction.

Isometric(increased pressure but no shortening)

Explanation:

Isometric contraction, is one in which the muscle is activated, but instead of being allowed to lengthen or shorten, it is held at a constant length.
An isometric exercise is a form of exercise involving the static contraction of a muscle without any visible movement in the angle of the joint.
Isometric exercises are contractions of a particular muscle or group of muscles. During isometric exercises, the muscle doesn't noticeably change length and the affected joint doesn't move. Isometric exercises help maintain strength. They can also build strength, but not effectively.
Isometric exercise is also known as static strength training. (Examples include the plank and side bridge as well as the wall sit and many yoga poses such as chair and tree poses).

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At the same moment from the top of a building 3.0 × 10 2 m tall, one rock is dropped and one is thrown downward with an initial

Bess [88]

The equation that relates distance, velocities, acceleration, and time is,
d = V₀t + 0.5gt²
where d is distance,
V₀ is the initial velocity,
t is time, and
g is the acceleration due to gravity (equal to 9.8 m/s²)

(1) Dropped rock,
(3 x 10² m ) = 0(t) + 0.5(9.8 m/s²)(t²)
The value of t from this equation is 24.73 s

(2) Thrown rock with V₀ = 26 m/s
(3 x 10² m) = (26)(t) + 0.5(9.8 m/s²)(t²)
The value of t from the equation is 5.61 s

The difference between the tim,
difference = 24.73 s - 5.61 s
difference = 19.12 s

<em>ANSWER: 19.12 s</em>

5 0

2 years ago

Read 2 more answers

Billiard ball A (0.35 kg) is struck such that it moves at 10 m/s toward a second identical ball (Ball B) initially at rest. Afte

timurjin [86]

Answer:

Explanation:

We shall apply law of conservation of momentum during the collision of ball A and B .

Total momentum before collision of A and B = .35 x 10 = 3.5 kg m/s

Let the velocity of B after collision be v .

Total momentum after collision = .35 x 2 + .35v

According to law of conservation of momentum

.35 x 2 + .35v = 3.5

.35 v = 2.8

v = 8 m /s .

The direction of B will be same as direction of A .

3 0

3 years ago

Please. Physics is so difficult.

Softa [21]

Answer:

0.010 m

Explanation:

So the equation for a pendulum period is: $y=2\pi\sqrt{\frac{L}{g}}$ where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:

$1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\$

Evaluate the multiplication in front

$1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}$

Divide both sides by 6.28

$0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}$

Square both sides

$0.100 s^2= \frac{L}{9.8 m\backslash s^2}$

Multiply both sides by m/s^2 (the s^2 will cancel out)

$0.984 m = L$

Now now let's find the length when it's two seconds

$2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}$

Divide both sides by 6.28

$0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}$

Square both sides

$0.101 s^2 = \frac{L}{9.8 m\backslash s^2}$

Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)

$0.994 m = L$

So to find the difference you simply subtract

0.984 - 0.994 = 0.010 m

4 0

1 year ago

Read 2 more answers

What is the unit of self inductance?

stira [4]

Answer:

The correct answer to that question is HENRY

6 0

3 years ago

Average speed equals distance divided by time. on a journey to the

Tanzania [10]

The average speed will be 2.38×10⁶ m/sec.The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.

<h3>What is the average speed?</h3>

The total distance traveled by an object divided by the total time taken is the average speed.

The speed calculated at any particular instant of time is known as the instantaneous speed.

Given data;

Distance travelled = 4.12x10¹⁶ meter

Time period= 1.73x10¹⁰ sec

The average speed is found as

$\rm V_{avg}= \frac{d}{t} \\\\\ \rm V_{avg}= \frac{4.12 \times 10^{16}}{1.73 \times 10^{10} } \\\\\ V_{avg}=2.38 \times 10^6 \ m/sec$

Hence, the average speed will be 2.38×10⁶ m/sec.

To learn more about the average speed, refer to the link;

brainly.com/question/12322912

#SPJ1

6 0

2 years ago